Ans: Option (1) Discontinuity at (1, 7), zero at ( negative four thirds , 0)

Explanation:
Given function:
$f(x) = \frac{3x^2 + x - 4}{x-1}$

Now if we plug in the x = 1, we would have discontinuity as function goes to infinity.

Now for f(1):
$f(x) = \frac{3x^2 + x - 4}{x-1} \\ f(x) = \frac{3x^2 + 4x - 3x - 4}{x-1} \\ f(x) = \frac{x(3x+4)-1(3x+4)}{x-1} \\ f(x) = \frac{(x-1)(3x+4)}{(x-1)} \\ f(x) = 3x+4 \\ now ~ insert ~ x=1: \\ f(1) = 3(1) + 4 = 7 \\ It~means~discontinuity~at~(1,7).\\ Now~let~us~find~zeros.\\ put~ f(x) = 3x+4 ~ equals~ to ~zero. \\ =\ \textgreater \ ~3x+4 = 0 \\ =\ \textgreater \ ~ x = \frac{-4}{3} \\ Hence~zeros=( \frac{-4}{3}, 0)$

5 0

3 years ago

Together, a skateboarder and a bicycle cost $199.00. The skateboard costs $51.00 less than the bicycle. How much does each cost?

WITCHER [35]

Answer:

Bike=125 Skateboard= 74

Step-by-step explanation:

x + (x-51)= 199

2x-51=199

2x=250

x=125

125+ (125-51)=199

125+74=199

7 0

3 years ago

How do you solve these problems? a. (2/7)x + 5= -21 and b. 1/2(18x-2)=0

Kryger [21]

A is x=-91
B is x=1/9

3 0

2 years ago