Answer:
∂u/∂xi = i·cos(sn)
Step-by-step explanation:
For u = sin(v), the partial derivative of u with respect to xi is ...
∂u/∂xi = cos(v)·∂v/xi
In this case, v=sn, and ∂sn/∂xi = i, so the derivatives of interest are ...
∂u/∂xi = i·cos(sn)
Put it in desmos and you'll answer will pop up on the graph just look at the middle point
Step-by-step explanation:
M(8.-2), M'(x,y) ,
=(-5,1)

--> x - 8 = -5 --> x= 3
---> y+2 = 1 --> y =-1
so M'(3,-1) and its reflection y-axis is (-3,-1)
To find the slope(m), you use the slope formula:
And plug in the two points
(x₁ , y₁) = (1, 0)
(x₂ , y₂) = (5, 3)

