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marishachu [46]

2 years ago

11

Write Standard Form Expanded Form And Word Form at the top of the page.Write five numbers that are atleast 8 digits long under s

tandard form.Write the expanded form and the word form for each number under the appropriate heading.

1 answer:

umka21 [38]2 years ago

8 0

12,345,678= 10,000,000+2,000,000+300,000+40,000+5,0000+600+70+8
I only did one but you get the idea :)

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A circle has a circumference of 7.85 yards what is the diameter of the well

Vsevolod [243]

2.5 yds
C=2πr
d=2r
Solving ford
d=C
π=7.85
π≈2.

4 0

3 years ago

10 binder; 60% off; 6% tax

laila [671]

Answer:

I'm going to assume that the binder is $10, and that the tax is applied after the 60% off, in which case the answer is $4.24

Step-by-step explanation:

10 * 10 = 100

6 * 10 = 60

10 - 6 = 4

6 / 25 = 0.24

4 + 0.24 = 4.24

Answer: $4.24

4 0

2 years ago

Estimates show that there are 1.4*10^8 pet fish and 9.4*10^6 pet reptiles in the United States.

Readme [11.4K]

$\bf \stackrel{fish}{1.4\times 10^8}~~+~~\stackrel{reptiles}{9.4\times 10^6}
\\\\\\
\stackrel{fish}{140000000}~~+~~\stackrel{reptiles}{9400000}\implies 
\begin{array}{rrrrllll}
140000000\\
+9400000\\
\text{\textemdash\textemdash\textemdash\textemdash\textemdash}\\
149400000
\end{array}\implies 1.494\times 10^8$

5 0

3 years ago

Question 10 [10 points] The number of frogs in a pond increases continuously at a rate proportional to the number present. There

White raven [17]

Answer:

a) 1325 frogs b)75.47 hours

Step-by-step explanation:

start = 150 frogs

after 4 hours = 530

1) figure out how many frogs per hour 530/4 = 132.5 frogs per hour

2) 10 hours after initial time * 132.5 frogs = 1325 frogs

3) Time to reach 10000 frogs is => 10000 / 132.5 = 75.47 hours

4 0

3 years ago

Two lamps marked 100 W - 110 V and 100 W - 220 V are connected i

ELEN [110]

<h2>Answer:</h2>

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

<h2>Step-by-step explanation:</h2>

Given:

<em>First lamp rating</em>

Power (P) = 100W

Voltage (V) = 110V

<em>Second lamp rating</em>

Power (P) = 100W

Voltage (V) = 220V

<em>Source</em>

Voltage = 220V

i. <u>Get the resistance of each lamp</u>.

Remember that power (P) of each of the lamps is given by the quotient of the square of their voltage ratings (V) and their resistances (R). i.e

P = $\frac{V^2}{R}$

<em>Make R subject of the formula</em>

⇒ R = $\frac{V^2}{P}$ ------------------(i)

<em />

<em>For first lamp, let the resistance be R₁. Now substitute R = R₁, V = 110V and P = 100W into equation (i)</em>

R₁ = $\frac{110^2}{100}$

R₁ = 121Ω

<em />

<em>For second lamp, let the resistance be R₂. Now substitute R = R₂, V = 220V and P = 100W into equation (i)</em>

R₂ = $\frac{220^2}{100}$

R₂ = 484Ω

<em />

<em />

ii.<u> Get the equivalent resistance of the resistances of the lamps.</u>

Since the lamps are connected in series, their equivalent resistance (R) is the sum of their individual resistances. i.e

R = R₁ + R₂

R = 121 + 484

R = 605Ω

iii. <u>Get the current flowing through each of the lamps. </u>

Since the lamps are connected in series, then the same current flows through them. This current (I) is produced by the source voltage (V = 220V) of the line and their equivalent resistance (R = 605Ω). i.e

V = IR [From Ohm's law]

I = $\frac{V}{R}$

I = $\frac{220}{605}$

I = 0.36A

iv. <u>Get the power consumed by each lamp.</u>

From Ohm's law, the power consumed is given by;

P = I²R

Where;

I = current flowing through the lamp

R = resistance of the lamp.

<em>For the first lamp, power consumed is given by;</em>

P = I²R [Where I = 0.36 and R = 121Ω]

P = (0.36)² x 121

P = 15.68W

<em>For the second lamp, power consumed is given by;</em>

P = I²R [Where I = 0.36 and R = 484Ω]

P = (0.36)² x 484

P = 62.73W

Therefore;

The power consumed in the lamp marked 100W - 110V is 15.68W

The power consumed in the lamp marked 100W - 220V is 62.73W

8 0

2 years ago