Answer: (a) $6,600
(b) $28,600
<u>Step-by-step explanation:</u>
Interest (I) = Principal (P) x rate (r) x time (t)
I = 22,000(0.06)(5)
= 6,600
Accrued (A) = Principal (P) + Interest (I)
A = 22,000 + 6,600
= 28,600
Hi there!
a. Find the displacement by plugging in the values of the interval:
f(2) - f(0) = 0 - 2 = -2 meters.
Average velocity is the slope, thus:
The average velocity for the interval is -1 m/s.
b. To find the speed at the endpoints, we must take the derivative to get the velocity equation:
f(t) = t² - 3t +2
f'(t) = 2t - 3, at t = 0, speed = |-3| = 3 m/s. At t = 2, speed = 2(2) - 3 = 1 m/s.
Acceleration is the second derivative, thus:
f''(t) = 2. The acceleration is 2 m/s² for both endpoints.
c. When the body changes direction, the first derivative changes signs. Thus:
0 = 2t - 3
3 = 2t, t = 1.5 sec. This is where the body changes direction.
D and B!! Hope this helped
The required plane Π contains the line
L: (-1,1,2)+t(7,6,2)
means that Π is perpendicular to the direction vector of the line L, namely
vl=<7,6,2>
It is also required that Π be perpendicular to the plane
Π 1 : 5y-7z+8=0
means that Π is also perpendicular to the normal vector of the given plane, vp=<0,5,-7>.
Thus the normal vector of the required plane, Π can be obtained by the cross product of vl and vp, or vl x vp:
i j k
7 6 2
0 5 -7
=<-42-10, 0+49, 35-0>
=<-52, 49, 35>
which is the normal vector of Π
Since Π has to contain the line, it must pass through the point (-1,1,2), so the equation of the plane is
Π : -52(x-(-1))+49(y-1)+35(z-2)=0
=>
Π : -52x+49y+35z = 171
Check that normal vector of plane is orthogonal to line direction vector
<-52,49,35>.<7,6,2>
=-364+294+70
=0 ok
Ok I think it’s 26 if I’m wrong sorry
