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andrew11 [14]
4 years ago
9

HELP you purchase a car using a $22,000 loan with a 6% simple interest rate for 5 years

Mathematics
1 answer:
Hunter-Best [27]4 years ago
7 0

Answer:  (a) $6,600

                (b) $28,600

<u>Step-by-step explanation:</u>

Interest (I) = Principal (P) x rate (r) x time (t)

I = 22,000(0.06)(5)

 = 6,600


Accrued (A) = Principal (P) + Interest (I)

A = 22,000 + 6,600

  = 28,600

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bazaltina [42]
34+4y=180 subtract 34 from both sides146 rewrite 4y=146 then divide 4 from both sides which is 36.5 round to 37
hope this helps have a nice day
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3 years ago
Can someone please help
mr_godi [17]
The discount is 10%

10\% = 0.10

4 \times 0.10 = 0.40

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4 years ago
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asambeis [7]

Answer:

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8 0
3 years ago
A solid is composed of squares and equilateral triangles. It’s net is shown below:
slamgirl [31]

Answer:

35 square units

Step-by-step explanation:

The surface area of the given solid will be the sum of areas of all of its sides. From the given figure we can see that the sides(faces) of the solid are:

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  • 3 Squares

The Area of each triangle is 4 square units. So we need to calculate the area of the squares.

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8 0
3 years ago
Read 2 more answers
For his exercise today, Manuel plans to both run and swim. Let r be the number of laps he runs and lets be the number of laps he
QveST [7]

Answer:

The Inequality describing the situation is 3r+2s>45.

Step-by-step explanation:

Let the number of laps he runs be 'r'

Let the number of laps he swims be 's'

Now Given:

Time required to run each lap = 3 min

Time required to swim each lap = 2 min

Total minutes he need to exercise more than 45

we need to write the Inequality representing the same.

Solution:

Now we can say that;

Time required to run each lap multiplied by the number of laps he runs plus Time required to swim each lap multiplied by the number of laps he swims should be greater than Total minutes he need to exercise.

framing in equation form we get;

3r+2s>45

Hence The Inequality describing the situation is 3r+2s>45.

6 0
3 years ago
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