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Rudiy27
3 years ago
10

TRUE OR FALSE! A query can have no more than three common interpretations.

Computers and Technology
1 answer:
Vanyuwa [196]3 years ago
8 0

A query can have no more than three common interpretations is false. A query is a search through a source to find the answer to something. A common interpretation are the items that pop up in in the first spots of the search query because they are the most relatable to the question. A common interpretation usually answers the question, but there are times that the question is more complex and needs to be search for longer within the sources that pop up.

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1. Separate valid and invalid variables:
DedPeter [7]

Firstly we explain the variable and the declaration rule for the variable and further separating the valid and invalid variables.

  • Whenever a user is given a question, variables are data values that can vary. for example  age, CSL, etc.
  • It may alter and during the execution of the program.
  • It's a storage space for memories.
  • It has a name that corresponds to the location.
  • Data is stored in the memory location.

The rule for variable declaration:

  • The names of your variables should be based on the phrases used in the subject area, and they should reflect the variable's function.
  • By removing spaces between the words, you can make variable names. Each word in the name should be capitalized, including prepositions and pronouns that are one letter long.
  • An underscore should never be used to start a variable name.
  • Single-character variable names should be avoided. For loop counters, only short variable names are permitted.
  • After the state that equals the "true" value, name variables that describe binary states ("true" or "false").

The valid variable is:

CSL, Age,CLS,SEE,Stop5for,Give, $shopping, and United.

The invalid variable is:

Mark-sheet, Tel $, Simple Interest, and 545Newton.

Learn more:

brainly.com/question/2684763

5 0
3 years ago
Malcolm Movers charges a base rate of $200 per move plus $150 per hour and $2 per mile. Write a program named MoveEstimator that
jeka94

Answer:

import java.util.Scanner;

public class MoveEstimator

{

public static void main(String[] args) {

   

    Scanner input = new Scanner(System.in);

    final int BASE_RATE = 200, RATE_PER_HOUR = 150, RATE_PER_MILE = 2;

    int hours, miles;

    double totalFee = 0.0;

   

 System.out.print("Enter the number of hours for a job: ");

 hours = input.nextInt();

 System.out.print("Enter the number of miles: ");

 miles = input.nextInt();

 

 totalFee = BASE_RATE + (hours * RATE_PER_HOUR) + (miles * RATE_PER_MILE);

 System.out.printf("For a move taking %d hours and going %d miles the estimate is $%.2f", hours, miles, totalFee);

}

}

Explanation:

*The code is in Java.

Create the Scanner object to be able to get input

Initialize the constant values using final keyword, BASE_RATE, RATE_PER_HOUR, RATE_PER_MILE

Declare the variables, hours, miles, totalFee

Ask the user to enter the hours and miles

Calculate the totalFee, add BASE_RATE, multiplication of  hours and RATE_PER_HOUR, multiplication of  miles and RATE_PER_MILE

Print the output as in required format

6 0
3 years ago
Ali rolled a ball down a hill. This graph shows the kinetic and potential energy of the moving ball.
denis23 [38]
Ghhsususuhwbababahaha
8 0
2 years ago
What is a computer?<br>please solve with explaining ​
ivann1987 [24]

Answer:

computer is a device for storing and processing data and also to communicate with people

5 0
2 years ago
2. A host computer with an IP address of 172.16.29.155 using a subnet mask of 255.255.255.0 and a gateway of 172.16.29.1 pings a
ASHA 777 [7]

Answer:

From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

Explanation:

<h2>ADDRESS RESOLUTION PROTOCOL (ARP)</h2>

Address Resolution Protocol (ARP) is a procedure for mapping a logical address known as the IP address to a physical address known as MAC (Media Access Control) address in a local area network. The job of the ARP is essentially to translate 32-bit addresses to 48-bit addresses and vice-versa when using IP Version 4 (IPv4) to communicate on the network.

Most of the computer programs/applications use logical address (IP address) to send/receive messages, however, the actual communication happens over the physical address (MAC address) this happens in the layer 2 of the OSI model. An ARP request is a broadcast, and an ARP response is a Unicast.

Scenarios when ARP is used:

Scenario-1: The sender is a host and wants to send a packet to another host on the same network.

·        Use ARP to find another host’s physical address

Scenario -2: The sender is a host and wants to send a packet to another host on another network.

·        Sender looks at its routing table.

·        Find the IP address of the next-hop (router) for this destination.

·        Use ARP to find the router’s physical address

Scenario -3: the sender is a router and received a datagram destined for a host on another network.

·        Router checks its routing table.

·        Find the IP address of the next router.

·        Use ARP to find the next router’s physical address.

Scenario -4: The sender is a router that has received a datagram destined for a host in the same network.

·        Use ARP to find this host’s physical address.

The situation in the question above falls under scenario-1. From the host IP address and subnet mask, you can tell that both computers are on the same network. Host 172.16.29.155 will need to send an ARP request broadcast for 172.16.29.83 so to get the MAC address and update its ARP table if the host 172.16.29.83 has not already done so.

7 0
3 years ago
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