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Murrr4er [49]
3 years ago
7

The function h(t) = 150 – 9t represents the height of a ball dropped from 150 feet after t seconds. What will the height of the

ball be after 1.4 seconds?
Mathematics
1 answer:
Alexxx [7]3 years ago
6 0

Answer:

I'm so sorry I can't help

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WORTH 15 POINTS PLEASE ANSWER ASAP!! MY YOUNGER BROTHER NEEDS HELP ON THIS!!!!<br> ∧ω∧
xxTIMURxx [149]

Answer:

Therefore,

AD = 7 unit

AE = 600 unit

EF = 30 unit

FB = 5 unit

Ar(EFGH)= 210 unit²

Ar(ABCD)= 4445 unit²

Step-by-step explanation:

Given:

Consider a rectangle ABCD as shown in the figure below where,

Area (ABCD) = 635 × 7 = 4445

Therefore length and width of a rectangle will be

LENGTH =635 = AB

WIDTH  = 7 = AD

To Find:

AE =?

EF = ?

FB = ?

Ar(EFGH)=?

Ar(ABCD) =?

Solution:

We know that area of the rectangle is given by

\textrm{Area of rectangle}= LENGTH\times WIDTH

\textrm{Area of rectangle ABCD}= 635\times 7=4445\ unit^{2}

Substituting the values we get

\textrm{Area of rectangle AEHD}= AE\times 7\\\\4200=AE\times 7\\\therefore AE=\dfrac{4200}{7}=600

Similarly for area rectangle FBCG,

\textrm{Area of rectangle FBCG}= FB\times 7\\\\35=FB\times 7\\\therefore FB=\dfrac{35}{7}=5

Now we have

AB = 635,

AE + EF + FB = 635\\\\600+EF+5=635\\\\EF=635 -605=30\\\therefore EF = 30

Similarly for area rectangle EFGH,

\textrm{Area of rectangle EFGH}= EF\times 7\\\\=30\times 7=210\ isunit^{2}

Therefore,

AD = 7 unit

AE = 600 unit

EF = 30 unit

FB = 5 unit

Ar(EFGH)= 210 unit²

Ar(ABCD)= 4445 unit²

5 0
3 years ago
Read 2 more answers
1. A tortoise is running on a long, moving sidewalk. Her pedometer doesn't report her speed, but she knows that—since she got on
Burka [1]

Answer:

the sidewalk speed q = 3km/hr

the tortoise speed p is 1.5 km/hr

Step-by-step explanation:

From the given information:

let the speed of the tortoise be p  & the speed of the sidewalk be q

she's been running for 40 minutes (40/60 = 2/3) and that she's travelled 3 kilometres

Thus,

p + q = \dfrac{3}{\dfrac{2}{3}}

p + q = 9/2

p + q = 4.5 ----- (1)

when returning, she travelled 3km in 2 hours

i.e. -p + q = 3/2

-p + q = 1.5   ----- (2)

Thus, by using the elimination method for equation (1) and (2)

  p + q = 4.5  ----- (1)

<u>-p + q   = 1.5 ----- (2)  </u>

<u>       2q =  6               </u>

q = 6/2

q = 3 km/hr

From equation (1)

p + q = 4.5

p + 3 = 4.5

p = 4.5 - 3

p = 1.5 km/hr

Therefore, the sidewalk speed q = 3km/hr and the tortoise speed p is 1.5 km/hr

8 0
3 years ago
BRAINLIEST ASAP! help pls
alexgriva [62]
Answer C

This is because the order can be switched but the answer will not change
3 0
3 years ago
Read 2 more answers
. Simplify the following expression by combining like terms:<br> 3a + 6ab + 9ab + 3(a + ab)
gladu [14]

Answer:

6a+18ab

I think is correct

3 0
3 years ago
Read 2 more answers
HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!
MA_775_DIABLO [31]
The answer is A, “Obtuse triangle.”
7 0
3 years ago
Read 2 more answers
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