Answer:
-7/20
Step-by-step explanation:
3/10 ÷ -6/7
Copy dot flip
3/10 * -7/6
-21/60
Divide the top and bottom by 3
-7/20
Answer:

Step-by-step explanation:
<u>Quadratic Equation</u>
A quadratic equation also called a second-degree equation is a special polynomial whose highest degree is two.
The general form of the quadratic equation is

Where a is known as the leading coefficient. Another form to write the quadratic equation is

Where x1 and x2 are the roots or zeroes of the equation.
We have the roots of the given equation are -2 and 2, and the leading coefficient is 3.
Plugging in the given values we have

Operating


0.6
you forgot the decimal point
60% move the decimal one time to the left
Answer:
a) P=2(L+W)
b)
c)-2 inch/hour
Step-by-step explanation:
given:
length of the rectangle as L inches
width of the rectangle as W inches
a) The perimeter is defined as <u>the measure of the exterior boundaries</u>
therefore, for the rectangle the perimeter 'P' will be
P= length of AB+BC+CD+DA (A,B,C and D are marked on the figure attached)
Now from figure
P= L+W+L+W
OR
=> P=2L+2W .....................(1)
b)now dp/dt can be found as by differentiating the equation (1)
.............(2)
c)Now it is given for the part c of the question that
L=40 inches
W=104 inches
dL/dt=2 inches/hour
dW/dt= -3 inches/hour (here the negative sign depicts the decrease in the dimension)
substituting the above values in the equation (2) we get


Open circle on 4 and shaded to the left is the correct characteristics of the graph of 
Option C is correct.
Step-by-step explanation:
We need to identify the characteristics of the graph of 
The graph will contain all values that are less than 4.
4 is not included in the graph because we have less than sign and not less than equal to. So, an open circle will appear on 4.
All values less than 4 are on the left of 4, so shaded to the left of the graph.
The graph of
is attached in the figure below.
So, open circle on 4 and shaded to the left is the correct characteristics of the graph of 
Option C is correct.
Keywords: Solving inequalities
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