Answer:
Step-by-step explanation:
Explanation:
Start by writing out your starting expression
x
2
−
5
x
2
+
5
x
−
14
−
x
+
3
x
+
7
Next, factor the denominator of the first fraction
x
2
+
5
x
−
14
x
2
+
7
x
−
2
x
−
14
x
(
x
−
2
)
+
7
(
x
−
2
)
(
x
−
2
)
(
x
+
7
)
Your expression is thus equivalent to
x
2
−
5
(
x
−
2
)
⋅
(
x
+
7
)
−
x
+
3
x
+
7
Since you have to subtract two fractions, you need to find the commonon denominator first. To do that, multiply the second fraction by
x
−
2
x
−
2
x
2
−
5
(
x
−
2
)
⋅
(
x
+
7
)
−
(
x
+
3
)
⋅
(
x
−
2
)
(
x
−
2
)
⋅
(
x
+
7
)
This will get you
x
2
−
5
−
(
x
+
3
)
(
x
−
2
)
(
x
−
2
)
(
x
+
7
)
x
2
−
5
−
x
2
−
x
+
6
(
x
−
2
)
(
x
+
7
)
=
1
−
x
(
x
−
2
)
(
x
+
7
)
Answer:
Therefore the answer is 20.
Step-by-step explanation:
We know that
class interval = range / number of classes
But here number of classes is not given , so we use the formula
class interval = range / ( 1+ 3.322 log N)
where , range =maximum - minimum = 220-100 = 120
N= number of observations = 50
class interval = 120 / ( 1+ 3.322 * log 50) = 18.06
Rounding up to a convinient number
Thus , class intervai = 20
Therefore the answer is 20.
Answer:
a square backyard with width (x - 9)
Step-by-step explanation:
x²−18x + 81 = x² - (2 x 9) x + 9² = (x - 9)²
width = area / length = (x - 9)² / (x - 9) = x - 9
Length = width
This is a square backyard
hope it will help you..........
Answer:2
Step-by-step explanation:
