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Artyom0805 [142]
4 years ago
12

2 fair dice are rolled. What is the probability that the sum is even given that the first die rolled is a 5?

Mathematics
1 answer:
sveticcg [70]4 years ago
4 0
The answer would be 50% because if the second die landed on three of the numbers (1, 3 or 5) the sum would be even (6, 8 or 10) but if it landed on the other three numbers (2, 4 and 6) the sum would be odd (7, 9 or 11)
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Please answer this correctly
just olya [345]

Hey there! :)

Answer:

P(factor of 40) ≈ 66.7%

Step-by-step explanation:

Begin by finding factors of 40 on the die:

1, 2, 4, 5.

Find probability of a factor of 40:

\frac{factors}{total}

There are 4 possible factors on a 6-sided die. Therefore:

\frac{4}{6} = \frac{2}{3}

Convert to percentage:

2/3 × 100 ≈66.7%. This is the probability for a factor of 40.

5 0
4 years ago
There are 9 students in the school choir. The ratio of girls to boys in the choir is 5 : 4. Two girls are absent from practice o
pishuonlain [190]

Answer:

5:9

Step-by-step explanation:

4 0
3 years ago
5v–5<5 for a two step linear equation
natta225 [31]

Step-by-step explanation:

5v - 5 < 5

Add 5 on both sides

5v - 5 + 5 < 5 + 5

5v < 10

Divide by 5 on both sides

V < 2

8 0
3 years ago
Can someone explain how to do this :) im very confused
Alecsey [184]

Answer:

the answer is 36q^7

Step-by-step explanation:

multiply the bases and add the exponents

3 0
3 years ago
5/3 - 1/5 = ? What is the answer
Sedbober [7]
<span><span>5/3</span>-<span>1/5</span></span><span>= <span>(5 × 5) - (1 × 3) 3 × 5 </span></span><span>= <span><span>1 7/</span><span>15

I hope this helps! Good luck :)

</span></span></span>
7 0
3 years ago
Read 2 more answers
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