Let there be x quarts of the 20% salt solution, and (25 - x) quarts of the 80% salt solution.
Then the total amount of salt in the 20% portion would be 0.2x, while that from the 80% portion would be (0.8)(25 - x). This would have to total up to (0.44)(25) in the final solution, so the equation is:
0.2x + 0.8(25 - x) = (0.44)(25)
-0.6x + 20 = 11
x = 15 quarts of the 20% salt solution
25 - x = 10 quarts of the 80% salt solution
(+/-) <span>1 x (+/-) 232 = 232
</span>(+/-) <span>2 x (+/-)116 = 232
</span>(+/-) 4 x (+/-) <span>58 = 232
</span>(+/-) 8 x (+/-) <span>29 = 232
</span>(+/-) 29 x (+/-) <span>8 = 232
</span>(+/-) 58 x (+/-) <span>4 = 232
</span>(+/-) 116 x (+/-) <span>2 = 232
</span>(+/-) 232 x (+/-) 1 = 232
Answer:
Population of mosquitoes in the area at any time t is:

Step-by-step explanation:
assume population at any time t = P(t)
population increases at a rate proportional to the current population:
⇒dP/dt ∝ P
----(1)
where k is constant rate at which population is doubled
solving (1)

---- (2)
initial population = 400,000
population is doubled every week
⇒P(1)=2P(0)
Using (2)


In presence of predators amount is decreased by 50,000 per day
Then amount decreased per week = 350,000
In this case (1) becomes
---(3)
solving (3) by calculating integrating factor

Multiplying I.F with all terms of (3)

Integrating w.r.to t




at t=0



So, population of mosquitoes in the area at any time t is

180
The exterior angle of a triangle + the adjacent interior angle are supplementary, that is sum to 180°, thus
the exterior angle = 180 - adjacent interior angle
Answer:
a=
or ≈ -3.66
Step-by-step explanation:
-(3a+4)=7
-3a-4=7
<em>Add 4 to both sides</em>
-3a=11
<em>Multiply both sides by -1</em>
3a= -11
Divide both sides by 3
a= 