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WINSTONCH [101]
2 years ago
9

Study the figure to answer the question.

Mathematics
1 answer:
mezya [45]2 years ago
4 0

Answer:

a cone with a radius of 4 units

Step-by-step explanation:

when rotating something, this involves a circle. so, the result will always be round and never edgy. therefrom the first option is wrong.

and we are rotating a triangle. the result will have a wide base and a pointed tip. so, the third option is wrong.

the rotation does not make the basic shape smaller. so, the second option is wrong.

yes, the fourth option is correct.

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A chemistry teacher needs to mix a 20% salt solution with a 80% salt solution to make 25 qt of a 44% salt solution. How many qua
NNADVOKAT [17]
Let there be x quarts of the 20% salt solution, and (25 - x) quarts of the 80% salt solution.
Then the total amount of salt in the 20% portion would be 0.2x, while that from the 80% portion would be (0.8)(25 - x). This would have to total up to (0.44)(25) in the final solution, so the equation is:
0.2x + 0.8(25 - x) = (0.44)(25)
-0.6x + 20 = 11
x = 15 quarts of the 20% salt solution
25 - x = 10 quarts of the 80% salt solution
5 0
3 years ago
What multiplied by what other then 2 equals 232
AlekseyPX
(+/-) <span>1 x (+/-) 232 = 232
</span>(+/-) <span>2 x (+/-)116 = 232
</span>(+/-) 4 x (+/-) <span>58 = 232
</span>(+/-) 8 x (+/-) <span>29 = 232
</span>(+/-) 29 x (+/-) <span>8 = 232
</span>(+/-) 58 x (+/-) <span>4 = 232
</span>(+/-) 116 x (+/-) <span>2 = 232
</span>(+/-) 232 x (+/-) 1 = 232
5 0
3 years ago
The population of mosquitoes in a certain area increases at a rate proportional to the current population, and in the absence of
Alexandra [31]

Answer:

Population of mosquitoes in the area at any time t is:

P(t) =504,943.26  -104,943.26e^{0.693t}

Step-by-step explanation:

assume population at any time t = P(t)

population increases at a rate proportional to the current population:

⇒dP/dt ∝ P

 \implies \frac{dP}{dt} =kP----(1)

where k is constant rate at which population is doubled

solving (1)

ln|P(t)|=kt +C\\P(t)= e^{kt+C}\\P(t)=Ce^{kt}

t=0\\P(0) = P_{o}\\\implies C= P_{o}\\P(t) =P_{o}e^{kt}\\ ---- (2)

initial population = 400,000

population is doubled every week

                                                 ⇒P(1)=2P(0)

Using (2)

                                 P_{o}e^{k(1)} = 2P_{o} e^{k(0)}\\

                                            e^{k} =2\\k=ln|2|\\

In presence of predators amount is decreased by 50,000 per day

Then amount decreased per week = 350,000

In this case (1) becomes

\frac{dP}{dt}=kP-350,000\\\frac{dP}{dt} - kP=-350,000\\ ---(3)

solving (3) by calculating integrating factor

                                          I.F=e^{\int-k dt}

Multiplying I.F with all terms of (3)

e^{-kt}\frac{dP}{dt} - ke^{-kt}P =-350,000 e^{-kt}\\\frac{d}{dt}(e^{-kt}P) =  -350,000 e^{-kt}

Integrating w.r.to t

                         e^{-kt}P(t)= \frac{350,000e^{-kt}}{k} +C

                         P(t) =\frac{350,000}{k} +Ce^{kt}\\

                                          k=ln|2| =0.693

                          P(t) =504,943.26 + Ce^{0.693t}\\

at t=0

                        P(0) =504,943.26 + Ce^{0.693(0)}

                        400,000 =504,943.26 + C

                           C = -104,943.26

So, population of mosquitoes in the area at any time t is

                  P(t) =504,943.26  -104,943.26e^{0.693t}

6 0
3 years ago
An exterior angle of a triangle equals _______ minus the adjacent interior angle. 90 270 180 360An exterior angle of a triangle
Romashka [77]

180

The exterior angle of a triangle + the adjacent interior angle are supplementary, that is sum to 180°, thus

the exterior angle = 180 - adjacent interior angle




7 0
3 years ago
Read 2 more answers
Solve the equation. Then check your solution.<br> -<br> (3a + 4) = 7<br> Helppp
Sati [7]

Answer:

a= -3\frac{2}{3} or ≈ -3.66

Step-by-step explanation:

-(3a+4)=7

-3a-4=7

<em>Add 4 to both sides</em>

-3a=11

<em>Multiply both sides by -1</em>

3a= -11

Divide both sides by 3

a= -3\frac{2}{3}

8 0
4 years ago
Read 2 more answers
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