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yulyashka [42]
4 years ago
13

Write an equation of a line in slope intercept form that is perpendicular to the line 2x -3y = 12 and

Mathematics
1 answer:
ella [17]4 years ago
3 0

Answer:

The equation of the line would be y = -3/2x + 9

Step-by-step explanation:

In order to solve this, start by finding the slope of the original line. You can do this by solving for y.

2x - 3y = 12

-3y = -2x + 12

y = 2/3x - 4

Now that we have a slope of 2/3, we know that the perpendicular slope is -3/2 (since perpendicular lines have opposite and reciprocal slopes). We can use this and the new point in point-slope form to find the equation.

y - y1 = m(x - x1)

y - 6 = -3/2(x - 2)

y - 6 = -3/2x + 3

y = -3/2x + 9

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sdas [7]

Answer:

-2 & 1/3

Step-by-step explanation:

When you set the two equations equal to each other, they form to parallel, vertical lines. They cross the x-axis at -2 and 1/3. Hope this helps.

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How many different arrangements are there of the letters a, b, c, d, e, f for which e is not last in line?
Olegator [25]
Hmm, there are 5 letters


if you cannot repeat the letters
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3 years ago
Determine the best method to solve the system of equations. Then solve the system.
maxonik [38]

Answer:

x=1  y = -1/2

(1,-1/2)

Step-by-step explanation:

7x-2y=8  

5x+2y=4

I would use elimination since we have 2y in one equation and -2y in the other

7x-2y=8  

5x+2y=4

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12x = 12

Divide each side by 12

12x/12 = 12/12

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The substitute back into equation 2

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What is the antiderivative of sin^2(x)cos^2(x)?
marin [14]

Answer:

\frac{x}{8}-\frac{\sin(4x)}{32}+C

Step-by-step explanation:

[Most of the work here comes from manipulating the trig to make the term (integrand) integrable.]

Recall that we can express the squared trig functions in terms of cos(2x). That is,

\cos(2x)=2\cos^2x-1 \\ \cos(2x)=1 - 2\sin^2x.

And so inverting these,

\cos^2x=\frac{1}{2} (1+\cos2x) \\ \sin^2x=\frac{1}{2} (1-\cos2x).

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