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4 years ago

Like terms are either_or they are terms with the same_that have the same ___

2 answers:

6 0

Like terms are either CONSTANTS, or they are terms with the same VARIABLE that have the same EXPONENT. Some examples: 9x and 5x are like terms because they both have the same variable (x) with the same exponent (1). however, 5 and 5x are not like terms, because one is a constant while the other has a variable. hope this helps you out

Maru [420]4 years ago

4 0

Like terms are either (3) exponents or they are terms with the same (1) constant that have the same (2) variables.

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For questions 4-5 find the area of the triangle given the answer to the nearest tenth 4.7 6.1

REY [17]

4.A=10.5 m2
5.B=63.4 cm2

8 0

4 years ago

: If f(x) = 3 + 2x - 10x^2, find f(-4)

a_sh-v [17]

Answer:

$f( - 4) = 3 + (2\times - 4) \\ = 3 - 8 \\ = - 5$

3 0

3 years ago

Read 2 more answers

A 500500-gallon tank initially contains 200200 gallons of brine containing 100100 pounds of dissolved salt. brine containing 11

mixer [17]

Let $A(t)$ denote the amount of salt in the tank at time $t$ . We're given that the tank initially holds $A(0)=100$ lbs of salt.

The rate at which salt flows in and out of the tank is given by the relation

$\dfrac{\mathrm dA}{\mathrm dt}=\underbrace{\dfrac{11\text{ lb}}{1\text{ gal}}\times\dfrac{44\text{ gal}}{1\text{ min}}}_{\text{rate in}}-\underbrace{\dfrac{A(t)}{200+(44-11)t}\times\dfrac{11\text{ gal}}{1\text{ min}}}_{\text{rate out}}$
$\implies A'(t)+\dfrac{11}{200+33t}A(t)=484$

Find the integrating factor:

$\mu(t)=\exp\left(\displaystyle\int\frac{11}{200+33t}\,\mathrm dt\right)=(200+33t)^{1/3}$

Distribute $\mu(t)$ along both sides of the ODE:

$(200+33t)^{1/3}A'(t)+11(200+33t)^{-2/3}A(t)=484(200+33t)^{-1/3}$
$\bigg((200+33t)^{1/3}A(t)\bigg)'=484(200+33t)^{-1/3}$
$A(t)=484\displaystyle\int(200+33t)^{-1/3}\,\mathrm dt$
$A(t)=22(200+33t)^{2/3}+C$

Since $A(0)=100$ , we get

$100=22(200)^{2/3}+C\implies C\approx-652.39$

so that the particular solution for $A(t)$ is

$A(t)=22(200+33t)^{2/3}-652.39$

The tank becomes full when the volume of solution in the tank at time $t$ is the same as the total volume of the tank:

$200+(44-11)t=500\implies 33t=300\implies t\approx9.09$

at which point the amount of salt in the solution would be

$A(9.09)\approx733.47\text{ lb}$

4 0

3 years ago

If 3/4 of the 1000 tickets were sold, how many tickets were sold?

-Dominant- [34]

Answer:

750 tickets were sold

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

The price of an item has been reduced by 85% . The original price was $45. What is the price of the item now.

Kobotan [32]

Answer:the price for the item now it's 6.75

Step-by-step explanation:

Origin price is 45=100% after reduction comes to 85% =x

X stands for the unknown value of the reduction therefore

45=100%

X=85%

45*.85=100x

After calculation you realised the value of x reduction value it's 38.25

Hence, original price is 45 your less from the value reduced 38.25 therefore the value of the item is 6.75

3 0

3 years ago

Like terms are either___or they are terms with the same___that have the same ___

Like terms are either_or they are terms with the same_that have the same ___