Here is my process for solving this.
First I drew arrows that indicated I was moving the whole triangle 5 units to the left.
*Look at first attachment*
Then I drew another triangle using those new points. (The new triangle is in pink)
*Look at second attachment*
Then I drew arrows that moved this new triangle 4 units up. (The new arrows are in pink)
*Look at third attachment*
Then I drew the new triangle in blue using the new points.
*Look at fourth attachment*
Then I mirrored / reflected the triangle over the x axis (the horizontal line) In green.
*Look at fifth attachment*
The fifth attachment in green is the final product! Hope that helps.
Vertex form:
y-k=a(x-h)^2
h=-2,k=-20,y=-12 when x=0
thus;
-12+20=a(0+2)^2
8=4a
a=2
Equation:
y+20=2(x+2)^2
y+20=2(x^2+4x+4)
f(x)=2(x^2+4x+4)-20
f(x)=2x^2+8x+8-20
f(x)=2x^2+8x-20
Answer:
no
Step-by-step explanation:
they are not like terms because the term 9x^2 is to the 2nd power which means that you are supposed to times the number by itself 2 times and 9x is not to the 2nd power so it stays the same.