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TiliK225 [7]
3 years ago
7

How many different arrangements are there of the letters a, b, c, d, e, f for which e is not last in line?

Mathematics
1 answer:
Olegator [25]3 years ago
6 0
Hmm, there are 5 letters


if you cannot repeat the letters
hmm, let's find how many for 4 letters
there are 4! or 4*3*2*1=24
that's how many ways there are to arrange a,b,c, d
now we can multiply it by 4 because there are 4 choices for the last place (e is not included0
24*4=56
answer is 56 different arrangements
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aalyn [17]
What’s the answer you have currently
3 0
3 years ago
Read 2 more answers
Please answer this for me
Bumek [7]

Answer:

422.39 sq cm

Step-by-step explanation:

Find the area of the circle and subtract the area of the rectangle from it.

Circle area: pi*12^2, 144pi sq cm

REctangle area: 10*3=30sq cm

144pi-30≈422.39

7 0
3 years ago
Can you help me out it would be much appreciate thank you
brilliants [131]

Answer:

The answer to the question is 50.28 feet²

Step-by-step explanation:

Here, is why the answer to the problem is 13.72!

The area of the shaded region is:-

Area of total region - Area of the circular region

Area of total region is 8² so it is 64 feet²

Area of Circular region formula is πr²

Substitute the values, for the formula and it is π4² = 22/7 × 16

                                                                         → 352/7

                                                                        ⇒ 13.72 Feet²

Therefore, the area of the shaded region is 13.72 Feet²

(Now, we subtract the two values)

64 - 13.72

⇒ 50.28 Feet²

I hope this answer helps!

7 0
2 years ago
3x+4/5=7-2x what does x=
klemol [59]

Answer:

x=31/25

Step-by-step explanation:

3x+4/5=7-2x

Multiply through by 5

5(3x+4/5)=5(7-2x)

15x+4=35-10x

Collecting like terms

15x+10x=35-4

25x=31

x=31/25

4 0
3 years ago
Find the six trigonometric function values for angle ∅ where its adjacent side is -9 and its hypotenuse is 41. (Theta is located
arsen [322]
Check the picture below.

\bf \textit{using the pythagorean theorem}
\\\\
c^2=a^2+b^2\implies \sqrt{c^2-a^2}=b
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\sqrt{41^2-(-9)^2}=b\implies \sqrt{1681-81}=b\\\\\\ \sqrt{1600}=b\implies 40=b\\\\
-------------------------------

\bf sin(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{hypotenuse}{41}}\qquad~~  cos(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{hypotenuse}{41}}\qquad~~  tan(\theta )=\cfrac{\stackrel{opposite}{40}}{\stackrel{adjacent}{-9}}
\\\\\\
csc(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{opposite}{40}}\qquad ~~sec(\theta )=\cfrac{\stackrel{hypotenuse}{41}}{\stackrel{adjacent}{-9}}\qquad ~~cot(\theta )=\cfrac{\stackrel{adjacent}{-9}}{\stackrel{opposite}{40}}

3 0
3 years ago
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