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k0ka [10]
3 years ago
5

Help me solve this problem please

Mathematics
1 answer:
ASHA 777 [7]3 years ago
5 0

Answer:

3x plus 5 is definetely greater than -16 cause of the negative and 8 is bigger also then a negative

Step-by-step explanation:

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What is the 2nd term of the linear sequence below? 5 , 8 , 11 , 14 , 17 , . . .
julia-pushkina [17]

Answer:

2nd term is 8.

nth term is 3n + 2.

Step-by-step explanation:

nth term = 5 + 3(n - 1)

= 3n + 2

5 0
3 years ago
I need help with Multiplication Properties of Exponents desperately!! I've tried to solve both problems repeatedly and I cannot
Yuliya22 [10]

Answer:

1) x= -36.

2) x = 0.

Step-by-step explanation:

1) Taking the 3rd power to both sides and using the following exponent law:

\left(a^b\right)^c = a^{bc}

we get:

\left(\left(m^{x}\right)^{\frac{1}{3}}\right)^3 = \left(m^{-12}\right)^3 \\ m^x = m^{-36}

So this tells us that x = -36.

2) We can distribute the power inside every term. So the left side becomes:

\left(3x^3y^x\right)^3 = 3^3\left(x^3)^3y^{3x} = 27x^9y^{3x}

Now, the trick here is to remember that y^0 = 1, so replacing 1 with y^0, which then gives us:

27x^9y^{3x} = 27x^9y^{0}, telling us that 3x = 0 and thus, x = 0.

7 0
3 years ago
Simplify completely 8x^3 ÷ 6x^2 - 4x / -2x
artcher [175]

Answer:

Simplified form is -(\frac{8x^{3}}{3x-2}).

Step-by-step explanation:

The given expression is 8x^{3}\div \frac{6x^{2}-4x}{-2x}

We can rewrite the given expression as = 8x^{3}\times (-\frac{2x}{{6x^{2}-4x}})

Further simplification of the expression gives =\frac{-16x^{4}}{6x^{2}-4x}

=\frac{-16x^{4}}{2x(3x-2)}

=-(\frac{8x^{3}}{3x-2})

So the simplified of the given expression is =[tex]-(\frac{8x^{3}}{3x-2})

3 0
3 years ago
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\huge\bf\red{answer}

<h2>The expression is not factorable with rational numbers.</h2>
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2 years ago
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erastovalidia [21]

Answer:a lot

Step-by-step explanation:

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