3 years ago

Michael thought he could only run 5 laps around the track but he was actually able to run 8 laps what was his percent error

Mathematics

1 answer:

abruzzese [7]3 years ago

6 0

Answer:

35.5 i think this is the right answer

You might be interested in

1/(cot^2 (x)) - 1/(cos^2 (x))

Airida [17]

Step-by-step explanation:

1 is your answer its law of trig identises

5 0

3 years ago

Read 2 more answers

What is the area of the triangle shown below?

bearhunter [10]

Answer:

Step-by-step explanation:

5 0

3 years ago

The temperature at 6:00 am was -12 Fahrenheit. The temperature increased by 1/2 Fahrenheit each hour for 6 hours. What was the t

zlopas [31]

Answer: -9°F

Step-by-step explanation:

From the question, we are told that the temperature at 6:00 am was -12 Fahrenheit and that the temperature increased by 1/2 Fahrenheit each hour for 6 hours.

The temperature, in degrees Fahrenheit, at noon would be:

= -12°F + 1/2(6)

= -12°F + 3°F

= -9°F

6 0

3 years ago

Using the primary trigonometric formulas you learned in Lesson 1, explain why the equation cos q = 1.4 has no solutions.

AysviL [449]

Answer:

see explanation

Step-by-step explanation:

For the equation to have solutions , then

- 1 ≤ cosq ≤ 1

Since cosq = 1.4 ( out with limits )

Then the equation has no solutions

8 0

3 years ago

Is the point P (2,8) on the inside or outside of the circle described with equation x^2+y^2=100?

kykrilka [37]

Points $(x,y)$ on the circle satisfy $x^2+y^2=100$ .

Points inside the circle satisfy $x^2+y^2$ .

Points outside the circle satisfy $x^2+y^2>100$ .

We have

$2^2+8^2=4+64=68$

so the point (2, 8) lies inside the circle.

6 0

3 years ago