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dsp73
4 years ago
5

Select the correct answer.

Mathematics
2 answers:
Misha Larkins [42]4 years ago
8 0

Answer:

1/3

Step-by-step explanation:

The only ways to get at least 30 cents from two coins are:

- 1 nickel (5 cents) + 1 quarter (25 cents)   -   case 1

- 1 dime (10 cents) + 1 quarter (25 cents)   -   case 2

- 1 quarter (25 cents) + 1 quarter (25 cents)   -   case 3

<u>Case 1</u>:

The probability of choosing a nickel is 1/3 and the probability of choosing a quarter next is also 1/3. Multiply these together:

(1/3) * (1/3) = 1/9

<u>Case 2</u>:

The probability of choosing a dime is 1/3 and the probability of choosing a quarter next is also 1/3. Multiply these together:

(1/3) * (1/3) = 1/9

<u>Case 3</u>:

The probability of choosing a quarter is 1/3 and the probability of choosing another quarter next is also 1/3. Multiply these together:

(1/3) * (1/3) = 1/9

Finally, add up these probabilities:

1/9 + 1/9 + 1/9 = 3/9 = 1/3

Lubov Fominskaja [6]4 years ago
4 0

Answer:

5/9

Step-by-step explanation:

Sum atleast 30 when:

Nickel and quarter

Quarter and nickel

Dime and quarter

Quarter and dime

Quarter and quarter

Total possibilities: 3×3 = 9

Probability = 5/9

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