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3 years ago

What is the point-slope form of a line that has a slope of –4 and passes through point (–3, 1)?

Mathematics

1 answer:

svet-max [94.6K]3 years ago

7 0

Answer:

y - 1 = - 4(x + 3)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = - 4 and (a, b) = (- 3, 1), thus

y - 1 = - 4(x - (- 3)), that is

y - 1 = - 4(x + 3)

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Convert into vertex form. Give the vertex.<br> y = 3x² – 24x + 46

gavmur [86]

Here you go! Hope this helps!!!

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2 years ago

What is the solution to this equation? 2x + 3 = x - 4

AfilCa [17]

Answer:

Step-by-step explanation:

First, isolate the variables onto one side of the equation.

2x + 3 = x - 4

(subtract x)

x + 3 = -4

Then, remove any remaining numbers.

(subtract 3)

x = -7

I hope this helps!

6 0

3 years ago

Which set includes rational numbers but not natural numbers?

Kryger [21]

Answer:

Answer: Natural Numbers count physical things. They can't be negative.

The third option is correct because its fractions and decimals.

Step-by-step explanation:

Hope this helps!

7 0

2 years ago

Read 2 more answers

What is it quick. And drop y’all Insta ask more

Tcecarenko [31]

Answer:

225 m2

Step-by-step explanation:

area= side*side

= 15x15

225 m2

4 0

2 years ago

What are the exact solutions of x2 − 5x − 7 = 0, where x equals negative b plus or minus the square root of b squared minus 4 ti

Marat540 [252]

Answer:

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

Step-by-step explanation:

Given

$x^2 - 5x - 7 = 0$

Required

Solve for x using:

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

First, we need to identify a, b and c

The general form of a quadratic equation is:

$ax^2 + bx + c = 0$

So, by comparison with $x^2 - 5x - 7 = 0$

$a = 1$ $b = -5$ $c = -7$

Substitute these values of a, b and c in

$x = \frac{-b \± \sqrt{b^2 - 4ac}}{2a}$

$x = \frac{-(-5) \± \sqrt{(-5)^2 - 4 * 1 * -7}}{2 * 1}$

$x = \frac{5 \± \sqrt{25 +28}}{2}$

$x = \frac{5 \± \sqrt{53}}{2}$

Split the expression to two

$x = \frac{5 + \sqrt{53}}{2}$ or $x = \frac{5 - \sqrt{53}}{2}$

To solve further in decimal form, we have

$x = \frac{5 + 7.28}{2}$ or $x = \frac{5 - 7.28}{2}$

$x = \frac{12.28}{2}$ or $x = \frac{-2.28}{2}$

$x = 6.14$ or $x = -1.14$

4 0

3 years ago