2 years ago

The axis of symmetry of a quadratic equation is x = –3. If one of the zeroes of the equation is 4, what is the other zero?

Mathematics

1 answer:

Irina-Kira [14]2 years ago

8 0

Answer:

-10

Step-by-step explanation:

If the axis of symmetry is at x = -3 and one of the zeros is at 4 then the other zero must be at equal distance from the axis , but on the other side, so will be at -10.

You might be interested in

5 times 3 times 2 <br><br> show work

guajiro [1.7K]

Answer:

Step-by-step explanation:

5x3=p

px2 = a

5x3 = 15 x 2 = 30

8 0

3 years ago

Read 2 more answers

Write 0.00052 in scientific notation.

Kamila [148]

10 over the power of negative 4

4 0

3 years ago

Geometry, Triangle in a circle. Find X show work and explain please

nikklg [1K]

Answer: $x=7$

Step-by-step explanation:

By the Intersecting Secants Theorem, we know that:

$(5)(x+5)=(6)(6+4)$

Having this, we can find the value of "x" by solving for "x":

Applying Distributive property:

$(5)(x+5)=(6)(24)\\5x+25=60$

Subtract 25 from both sides of the equation:

$5x+25-25=60-25\\5x=35$

And finally dviding both sides of the equation by 5, we get:

$\frac{5x}{5}=\frac{35}{5}\\x=7$

7 0

3 years ago

CAN I GET SOMEONES HELP ASAP!!

Elena L [17]

Corresponding angles are in the same relative position of an intersection.

The matching corner to VQR would be ZRT

8 0

3 years ago

George puts the chopped apples in a bowl then he takes out one half cup of apples and adds the oil what is the combined amount o

choli [55]

Spaghetti is always the answer

5 0

4 years ago