How do I simplify this? Thanks!

sarah meeham blends coffee for tasti delight. she needs to prepare 160 pounds of blended coffee beans selling for $4.97 per poun

Viefleur [7K]

Given:
h = high quality bean ; costs 6 per pound
c = cheaper bean ; costs 3.25 per pound

160 pounds of blended coffee beans at 4.97 per pound

h + c = 160

6h + 3.25c = 160(4.97)
6h + 3.25c = 795.20

h = 160 - c

6(160-c) + 3.25c = 795.20
960 - 6c + 3.25c = 795.20
- 2.75c = 795.20 - 960
- 2.75c = -164.80
c = - 164.80 / -2.75
c = 59.92 or 60 pounds

h = 160 - c
h = 160 - 60
h = 100 pounds

Sarah must blend 100 pounds of high quality bean and 60 pounds of cheaper bean.

3 0

3 years ago

Carly needs $149 to buy a skateboard. She already has $52. She earns money washing cars for $20 a car.

Blababa [14]

Answer:

$149 - skateboard price

$52 - carly's money

$20 × 5 cars = $100

$100 + $52 = $152

$152 - $149 = $3 left

5 0

2 years ago

Gloria decides to buy 4 ferns, 2 Palms, 10 Lilies and 8 shrubs. To show the total

Vadim26 [7]

Answer:

$Total Plants = 4F + 2P + 10L+ 8S$

$Total Plants = 2(2F + P + 5L+ 4S)$ --- Distributive property

Step-by-step explanation:

Given

Ferns = 4

Palms = 2

Lillies = 10

Shrubs = 8

Required

Show the total cost of plants as an expression

Shorten it using the distributive property

First, represent Ferns with F; Palms with P; Lilies with L and Shrubs with S;

So, 4 Ferns = 4F

2 Palms = 2P

10 Lilies = 10L

8 Shrubs = 8S

Total Plants = Summation of the above parameters

$Total Plants = 4F + 2P + 10L+ 8S$

The above expression represents the total plants bought;

Now, to apply the distributive property; we simply look for a common factor;

In this case, the common factor is 2;

So, $Total Plants = 4F + 2P + 10L+ 8S$ becomes

$Total Plants = 2(\frac{4F}{2} + \frac{2P}{2} + \frac{10L}{2}+ \frac{8S}{2})$

$Total Plants = 2(2F + P + 5L+ 4S)$

7 0

2 years ago

1. Find the distance between two

BigorU [14]

Answer:

$\mathrm{D)\:}9.4\: \mathrm{units}$

Step-by-step explanation:

<u>Solution 1:</u>

Notice the $x$ coordinate of both points are equal, meaning both points are on a vertical line. The distance between two points on a vertical line is the absolute difference of their y-coordinates. The absolute difference between $4.7$ and $-4.7$ is $|4.7-4.7|=\fbox{$9.4$}$ .

<u>Solution 2:</u>

The distance between two points $(x_1,y_1)$ and $(x_2,y_2)$ is:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Plugging in given values, we have:

$d=\sqrt{(-2.6-(-2.6))^2+(4.7-(-4.7))^2},\\d=\fbox{$9.4$}$ .

8 0

2 years ago

drag the gray arrow so that it is pointing midway between horizontal and vertical, heading downward and toward the right. extend

alex41 [277]

The speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

A star moving away from the observer (say on Earth) will have its emitted light red-shifted (move to lower frequency), i.e., the spectrum moving to left if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving towards the observer (say on Earth) will have its emitted light blue-shifted (move to higher frequency), i.e., the spectrum moving to the right if we consider the intensity of light is plotted as a function of frequency with the frequency increasing from left to right.

A star moving perpendicular to the observer (say on Earth) will have its emitted light will no change with respect to the spectrum of the stationary star.

These are due to the Doppler effect, the equation of frequency detected by the observer as

$f_o = f_s\sqrt{\frac{1-\beta }{1+\beta } }$ where $\beta = \frac{v}{c}$ , v the relative velocity of the moving source (the star here), f^s is the frequency of light emitted by the source.

Hence the answer is the speed of the star as compared to the speed of the star relative to earth is the frequency of light emitted by the source.

To learn more about frequency click here brainly.com/question/26177128

#SPJ4

7 0

8 months ago