WHERE DO I DRAG THE LAST TWO

Mathematics

1 answer:

Anastasy [175]3 years ago

4 0

-3/4 goes between -1 and 0 it is the 3rd line to the left and n would go between positive 0 and 1 on the 3rd line to the right

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Rick has 1/2 of a footlong sub left from yesterday. He ate 1/3 of the leftover sandwich as a snack. What fraction of the entire

Lelechka [254]

The answer is 1/6 of the sandwich

8 0

3 years ago

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Is x+y+1=0 a tangent of both y^2=4x and x^2=4y parabolas?

Lubov Fominskaja [6]

Answer:

yes

Step-by-step explanation:

The line intersects each parabola in one point, so is tangent to both.

For the first parabola, the point of intersection is ...

y^2 = 4(-y-1)

y^2 +4y +4 = 0

(y+2)^2 = 0

y = -2 . . . . . . . . one solution only

x = -(-2)-1 = 1

The point of intersection is (1, -2).

For the second parabola, the equation is the same, but with x and y interchanged:

x^2 = 4(-x-1)

(x +2)^2 = 0

x = -2, y = 1 . . . . . one point of intersection only

___

If the line is not parallel to the axis of symmetry, it is tangent if there is only one point of intersection. Here the line x+y+1=0 is tangent to both y^2=4x and x^2=4y.

_____

Another way to consider this is to look at the two parabolas as mirror images of each other across the line y=x. The given line is perpendicular to that line of reflection, so if it is tangent to one parabola, it is tangent to both.

7 0

2 years ago

Only find the vertex and axis of symmetry

lara [203]

Answer:

vertex (5,2)

axis of symmetry: x=5

Step-by-step explanation:

vertex (h,k)

y = a(x - h)² + k

f(x)=(x-5)²+2 a = 1 h = 5 k = 2

vertex (5 , 2)

The axis of symmetry always passes through the vertex of the parabola. The x -coordinate of the vertex is the equation of the axis of symmetry of the parabola.

x = 5