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iren [92.7K]
4 years ago
9

WHERE DO I DRAG THE LAST TWO

Mathematics
1 answer:
Anastasy [175]4 years ago
4 0
-3/4 goes between -1 and 0 it is the 3rd line to the left and n would go between positive 0 and 1 on the 3rd line to the right
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4w+5z=30 solve for w
zepelin [54]

Answer:

w=\frac{30-5z}{4}

Step-by-step explanation:

4w+5z=30\\\\4w+5z-5z=30-5z\\\\4w=30-5z\\\\\frac{4w=30-5z}{4}\\\\\boxed{w=\frac{30-5z}{4}}

Hope this helps.

3 0
3 years ago
I will mark you brainiest if you can answer this
yanalaym [24]
22 touchdowns and 13 field goals
7 0
3 years ago
Solve |4 - 2x| = |3x + 2|.
Vladimir79 [104]

Answer:

A

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Media experts claim that daily print newspapers are declining because of Internet access. Listed​ below, from left to right and
yKpoI14uk [10]

Answer:

(a) The median is 1478

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The test statistic  t_{\alpha/2} is 6.678155

(d) The p value is  1.2×10⁻¹¹

(e) We reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high

Step-by-step explanation:

(a) Here we have the data as follows;

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484 1478 1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The median is = 1478

Therefore we have above the median  

1623 1586 1574 1554 1544 1531 1519 1513 1491 1484

The mean,  \bar{x}_{1}= 1541.9

Standard deviation, σ₁ = 41.38224257

n₁ = 10

Below the median  

1471 1458 1456 1458 1453 1438 1428 1405 1395 1377

The mean,  \bar{x}_{2}}= 1433.9

Standard deviation, σ₂ = 30.04812806

n₂ = 10

(b) Null hypothesis H₀ : μ₁ = μ₂

Alternative hypothesis Hₐ : μ₁ > μ₂

(c) The formula for t test is given by;

t_{\alpha/2} =\frac{(\bar{x}_{1}-\bar{x}_{2})}{\sqrt{\frac{\sigma_{1}^{2} }{n_{1}}-\frac{\sigma _{2}^{2}}{n_{2}}}}

df = 10 - 1 = 9, α = 0.05

Therefore, the test statistic  t_{\alpha/2} = 6.678155

(d) The p value from statistical relations is Probability p = 1.2×10⁻¹¹

Critical z at 5% confidence level = 1.645

Since P << 0.05, e reject the

(e) Therefore, we reject our null hypothesis H₀. In terms of the test, there is sufficient evidence to suggest that there is a trend in the numbers of daily newspaper because the probability for a decrease in the numbers is very high.

5 0
3 years ago
Please help! Will mark Brainiest!
DochEvi [55]

Answer:

27.93 square yard

Step-by-step explanation:

For semicircle:

Radius (r) = 7 yards

For Triangle:

b = 2r = 2*7 = 14 yd

h = 7 yard

Area of shaded region = Area of semicircle - Area of triangle

= \frac{1}{2}  \times \pi {r}^{2}  -  \frac{1}{2}  \times b \times h \\  \\  =  \frac{1}{2}  \times 3.14 \times  {7}^{2}  -  \frac{1}{2}  \times 14\times 7 \\  \\  = \frac{1}{2}  \times 3.14 \times  49  -  \frac{1}{2}  \times 98\\  \\  = 3.14 \times 24.5 - 49 \\  \\  = 76.93 - 49  \\  \\  = 27.93 \:  {yd}^{2}  \\

7 0
3 years ago
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