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Arisa [49]
3 years ago
13

What is the expanded form of (x-2)(x+2)

Mathematics
2 answers:
Stels [109]3 years ago
6 0

Answer:

(x^2)-4

Step-by-step explanation:

expand using the distributive property of multiplication

shutvik [7]3 years ago
6 0

Answer:

(x^2)-4

Step-by-step explanation:

Distributive property of multiplication

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3/4a=24<br> A.18<br> B.4<br> C.32<br> D.6
zavuch27 [327]
3\4a=24 multiply both sides by 4 to get rid of 4(4 x 24=96)
3a=96 divide both sides by 3 to remain with a
a=32
8 0
3 years ago
Consider the rule y = 5x + 7.
maksim [4K]

Answer:

see below

Step-by-step explanation:

Consider the rule y = 5x + 7.

a. How many tiles are in Figure 0?

In figure 0, we let x=0

y = 5*0+7 = 0+7 = 7

b. Which figure has 37 tiles?

This means y = 37

37 = 5x+7

Subtract 7 from each side

37-7 = 5x+7-7

30 = 5x

Divide by 5

30/5 = 5x/5

6 =x

Figure 6 has 37 tiles

c. In the equation y = mx + b, what do the letters m and b represent?

m is the slope or how much it is increasing each time x increases by 1  and b is how much we start with when x =0

5 0
3 years ago
An online retailer offers next-day shipping for an extra fee. The retailer says that 95% of customers who pay for
alekssr [168]

Answer:

Step-by-step explanation:

4 0
3 years ago
A candy store has ten giant pieces of candy! Find the probability of each event. There are 4 gumdrops, 3 lolipops, 2 jellybeans,
AveGali [126]

Answer:

1. P = 9/90 = 1/10

2. P = 16/90 = 8/45

3. P = 10/90 = 1/9

4. P = 4/90 = 2/45

Step-by-step explanation:

Total no. of candy = 10

No. of Gumdrops = 4

No. of Lollipops = 3

No. of Jellybeans = 2

No. of Peppermint = 1

1. To find the probability that the child will pick a peppermint or jellybean, we will add the probabilities of both the candies.

P(Peppermint) = No. of Peppermint/Total no. of candy

                        = 1/10

P(Jellybean) = No. of Jellybean/Total no. of candy

                    = 2/10

P(Peppermint or Jellybean) = 1/10 + 2/10

P(Peppermint or Jellybean) = 3/10

Then, the child picks a lollipop. Note that after picking a peppermint or a jellybean, the number of candies left are 9. So,

P(Lollipop) = No. of Lollipops/Total no. of candy

P(Lollipop) = 3/9

To compute the probability that the child will pick a peppermint or a jellybean and then a lollipop,

P = P(Peppermint or Jellybean) x P(Lollipop)

  = 3/10 x 3/9

P = 9/90 = 1/10

2. Probability that a child will pick a lollipop or peppermint:

P(Lollipop or Peppermint) = P(lollipop) + P(peppermint)

                                          = 3/10 + 1/10

P(Lollipop or Peppermint) = 4/10

Then the child picks a gumdrop. Note that the number of candies remaining are 9. So,

P(Gumdrop) = 4/9

The probability that the child picks a lollipop or peppermint and then a gumdrop:

P = P(Lollipop or Peppermint) x P(Gumdrop)

  = 4/10 x 4/9

P = 16/90 = 8/45

3. Probability that a child will pick a jellybean:

P(Jellybean) = No. of Jellybeans/Total no. of candy

P(Jellybean) = 2/10

Then the child picks a peppermint or a gumdrop. Note that one candy has been picked out so there are 9 candies left in total.

P(Peppermint or Gumdrop) = P(peppermint) + P(Gumdrop)

                                              = 1/9 + 4/9

P(Peppermint or Gumdrop) = 5/9

The probability that a child picks a jellybean then a peppermint or a gumdrop is:

P = P(Jellybean) x P(Peppermint or Gumdrop)

  = 2/10 x 5/9

P = 10/90 = 1/9

4. P(peppermint) = 1/10

Then the child picks a gumdrop. (remaining candies are 9)

P(Gumdrop) = 4/9

Probability that a child will pick a peppermint then a gumdrop:

P = P(peppermint) x P(gumdrop)

  = 1/10 x 4/9

P = 4/90 = 2/45

5 0
3 years ago
N/8 + 1 = -25 what is n?
astra-53 [7]

Answer: =2

Step-by-step explanation

:Solve the rational equation by combining expressions and isolating the variable  

n

.

n

=

2

8 0
4 years ago
Read 2 more answers
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