I=k/d^2
4=k/d^2 and 1=k/64 so if we divide the first by the second we get:
4/1=(k/d^2)/(k/64)
4=(k/d^2)*(64/k)
4=64/d^2
d^2=64/4
d^2=16
d=4 meters
Let x = number of years between 1990 and 2000.
Rainbow smelt:
Initial population = 227
Average yearly rate of change = -19.76
The linear function that models the population is
y₁ = 227 - 19.76x
Bloater fish
Initial population = 1052
Average yearly rate of change = -92.57
The linear function that models the population is
y₂ = 1052 - 92.57x
When the two populations are equal, then y₁ = y₂.
That is
227 - 19.76x = 1052 - 92.57x
(92.57 - 19.76)x = 1052 - 227
72.81x = 825
x = 11.33 years
= 11 years, 0.33*12 months
= 11 years, 4 months
Add x to 1990 to obtain the year April 2011.
Answer:
x = 11.33 years.
This occurs in April 2001.
The following list gives the number of public libraries in each of 11 cities. 7, 11, 8, 7, 8, 7, 8, 11, 8, 10, 7 Find the modes
AlladinOne [14]
Answer:
The mode are: 7, 8
Step-by-step explanation:
Given

Required
Determine the mode
We start by arranging the given data in ascending order
The ordered data are:

From the above data.
7 has a frequency of 4
8 has a frequency of 4
10 has a frequency of 1
11 has a frequency of 2
The data with the highest frequency is the mode.
We can see that 7 and 8 both have frequencies of 4
<em>Hence, the mode are: 7, 8</em>