Histograms are used to represent data, where the length of each bar represents the frequency of the data element
The histogram is not given; So, I will give a general explanation.
Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.
The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.
So, we have:
Divide 450 by 500
Express as percentage
Hence, the percentage of commuters that travel more than 45 minutes is 90%
Read more about histograms at:
brainly.com/question/2776232
Answer:
y=-5x-2
Step-by-step explanation:
y=mx+b
where m is the slope
y=-5x+b
to solve for b, which is the y intercept, plug in (1,-7)
-7=-5(1)+b
-7=-5+b
-2=b
y=-5x-2
Answer:
See answer below
Step-by-step explanation:
The statement ‘x is an element of Y \X’ means, by definition of set difference, that "x is and element of Y and x is not an element of X", WIth the propositions given, we can rewrite this as "p∧¬q". Let us prove the identities given using the definitions of intersection, union, difference and complement. We will prove them by showing that the sets in both sides of the equation have the same elements.
i) x∈AnB if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.
ii) (I will abbreviate "if and only if" as "iff")
x∈A∪(B\A) iff x∈A or x∈B\A iff x∈A or x∈B and x∉A iff x∈A or x∈B (this is because if x∈B and x∈A then x∈A, so no elements are lost when we forget about the condition x∉A) iff x∈A∪B.
iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).
iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).
Answer:
Step-by-step explanation:
Think of a rational number as a fraction. The definition of a rational number is that it is the ratio of integers that, when divided, is either an integer, a decimal that terminates, or a decimal that repeats. 6/3 = 2 (6/3 is a rational number that divides to 2); 1/2 = .5 (1/2 is a rational number that divides to .5 which is a terminating decimal, meaning it ends); 1/3 = .33333333 (1/3 is a rational number that divides to .3333333 which is a repeating decimal). If we want to express 3.24 as a rational number, let's first put it into fraction form. The 4 in .24 is in the hundredths place, so as a fraction, .24 is 24/100. Check this on your calculator. Divide 24 by 100 and you get .24. So now what we have is 
Now express that mixed fraction as an improper and you're done. 3 times 100 is 300; 300 + 24 = 324. Put that back over 100 and your rational number is 324/100. Check that on your calculator, as well, just to see that it's true.
About 43 roomsAbout 43 roomsvAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 roomsAbout 43 rooms
