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LenKa [72]
1 year ago
14

Pollsters are concerned about declining levels of cooperation among persons contacted in surveys. A pollster contacts 81 people

in the 18-21 age bracket and finds that 69 of them respond and 12 refuse to respond. When 301 people in the 22-29 age bracket are contacted, 282 respond and 19 refuse to respond. Assume that 1 of the 382 people is randomly selected. Find the probability of getting someone in the 18-21 age bracket or someone who agreed to respond.
Mathematics
1 answer:
ipn [44]1 year ago
7 0

Answer:

Prob = 95.0%

Explanation:

There are 382 people in total

69 respond and are in the 18-21 age bracket

12 refuse to respond and are in the 18-21 age bracket

282 respond and are in the 22-29 age bracket

19 refuse to respond and are in the 22-29 age bracket

Then, the number of people that are in the 18-21 age bracket or agreed to respond is

69 + 12 + 282 = 363

Therefore, the probability of getting someone in the 18-21 age bracket or someone who agreed to respond is

P = 363/382

P = 0.9502

P = 95.0 %

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Histograms are used to represent data, where the length of each bar represents the frequency of the data element

The histogram is not given; So, I will give a general explanation.

Assume that the number of commuters that travel more than 45 minutes is 450, while the total number of commuters surveyed is 500.

The percentage of commuters that travel more than 45 minutes is the quotient of the commuters that travel more than 45 minutes and the total number of surveyed commuters.

So, we have:

\%Percentage = \frac{450}{500}

Divide 450 by 500

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Express as percentage

\%Percentage = 90\%

Hence, the percentage of commuters that travel more than 45 minutes is 90%

Read more about histograms at:

brainly.com/question/2776232

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y=-5x-2

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Answer:

See answer below

Step-by-step explanation:

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i) x∈AnB  if and only (if and only if means that both implications hold) x∈A and x∈B if and only if x∈A and x∉B^c (because B^c is the set of all elements that do not belong to X) if and only if x∈A\B^c. Then, if x∈AnB  then x∈A\B^c, and if x∈A\B^c then x∈AnB. Thus both sets are equal.

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iii) x∈A\(B U C) iff x∈A and x∉B∪C iff x∈A and x∉B and x∉C (if x∈B or x∈C then x∈B∪C thus we cannot have any of those two options). iff x∈A and x∉B and x∈A and x∉C iff x∈(A\B) and x∈(A\B) iff x∈ (A\B) n (A\C).

iv) x∈A\(B ∩ C) iff x∈A and x∉B∩C iff x∈A and x∉B or x∉C (if x∈B and x∈C then x∈B∩C thus one of these two must be false) iff x∈A and x∉B or x∈A and x∉C iff x∈(A\B) or x∈(A\B) iff x∈ (A\B) ∪ (A\C).

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