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patriot [66]
3 years ago
13

What is the absolute value of Point B labelled on the number line? A number line with point A at coordinate negative 2.2, point

B at coordinate negative 1.6, and point C at coordinate 1.2. Drag and drop the answer into the box to match the correct statement. HELP PLEASE
Mathematics
1 answer:
bulgar [2K]3 years ago
7 0

Answer:

The absolute value of point B on the number line is 2.2.

Step-by-step explanation:

A number line is given with point A at coordinate negative 2.2, point B at coordinate negative 1.6, and point C at coordinate 1.2.

So, on the number line, all the points having negative value are on the left side of zero.

Position of the point A is -2.2,

Position of the point B is -1.6,

Position of the point C is -1.2.

The absolute value of any point on the number line is the distance of that point from zero.

So, the absolute value of point B on the number line is the distance of point B from zero which is |-2,2|=2.2.

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Three years back , a father was 24 years older than his son .at present,the father is five times as old as the son.how old will
azamat

Answer:

The son is 5 I think

Step-by-step explanation:

24+3=27

27 divided by 5 = 5.4

round 5.4 to 5 since it is under .5

and you get 5

3 0
3 years ago
What is the product in lowest terms?
Alisiya [41]
-5/12 × 8/13

First, we need to start out by applying the multiplication rule towards fractions. If you haven't learned or don't remember the rules, you can always look up fraction rules. The rule is: a/b × c/d = ac/bd. Basically, we are combining the numerators and both of the denominators.
- \frac{5 \times 8}{12 \times 13}

Second, let's now multiply what we have in the fraction. (5 × 8 = 40) and (12 × 13 = 156). Doing so will create a new fraction for us to use.
-\frac{40}{156}

Third, now obviously, we can simplify the fraction we just got into lower terms. To do that, we have to collect the greatest common factor (GCF) of both the numerator and denominator and list their factors to find the common factor that is the greatest.

Factors of 40: 1, 2, 4, 5, 8, 10, 20, 40
Factors of 156: 1, 2, 3, 4, 6, 12, 13, 26, 39, 52, 78, 156

Out of the listed factors, which of those are the common ones? 1, 2, and 4 are the common factors. Since we are looking for the greatest common factor, it would be 4 since that is the higher number out of the commons. The GCF is 4.

Fourth, we can now divide our numerator (40) and our denominator (156) by the GCF we just found out, which was 4. 
40 \div 4 = 10  \\ 156 \div 4 = 39

Fifth, our last step is to create our new simplified fraction. All we have to do is take our new numerator and denominator to see the fraction. 

Answer in fraction form: \fbox {-10/39}
Answer in decimal form: \fbox {-0.2564}
4 0
3 years ago
10ft 19 ft how do you do this
tino4ka555 [31]
 If we're talking about a box with dimensions 10 ft, 19 ft and 20 ft, it's probable that the instructions say to calculate the volume.  That would be

V = (10 ft)(19 ft)(20 ft) = 3800 cubic feet.
8 0
3 years ago
PLEASE HELP IM SO STUCK ILL MARK YOU BRIANLIEST!!! 30 POINTS Given the expression: 6x10 − 96x2 Part A: Rewrite the expression by
Murljashka [212]

Answer:

6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)

Step-by-step explanation:

6x^10 − 96x^2

Factor out 6x^2

6x^2 ( x^8 - 16)

Notice that inside the parentheses we have the difference of squares

6x^2 ( x^4 ^2 - 4^2)  a^2 - b^2 = (a-b) (a+b)

6x^2 ( x^4 -4) (x^4 +4)

Notice that x^4-4 is also the difference of squares

6x^2 ( x^2^2 -2^2) (x^4 +4)

6x^2 ( x^2 -2) ( x^2 +2) (x^4 +4)

Note also that x^4 + 4 can be factored into (x^2+2x+2)(x^2-2x+2)

6x^2 ( x^2 -2) ( x^2 +2)(x^2+2x+2)(x^2-2x+2)

3 0
3 years ago
Alice and Bob both go to a party which starts at $5:00$. Each of them arrives at a random time between $5:00$ and $6:00$. What i
faltersainse [42]

The probability comes out to be 9/32.

Deducing Arrival Time Possibility

All the possible arrival times by Alice and Bob, in minutes after 5 PM, is constrained by the values of given values of x and y,

x = 0, y = 0, x = 60, y = 60.

Here, let the values of x represent how many minutes after 5 PM Alice arrives at the party.

Let the y values represent the time in minutes that Bob arrives at the party after 5 PM.

Calculating the Required Probability

The times that concern us, however, are obtained by the following probability function,

x + y ≤ 45.

And x = 0, y = 0, and x + y ≤ 45 define the constraints of this probability function. Thus the perimeter of such a graph will be given as,

(45² / 2) = 1012.5 square units

Since the total area of the various arrival times is 60 x 60, or 3600 square units, the probability that Alice and Bob will arrive together after 5 o'clock in the evening in less than 45 minutes is therefore = 1012.5 / 3600 = 9/32

Learn more about probability here:

brainly.com/question/11234923

#SPJ4

3 0
2 years ago
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