All categories

3 years ago

I) -7s (S-4t-3u) ii) -4c (2c-5d)

Mathematics

2 answers:

kari74 [83]3 years ago

8 0

Answer:

I) -7 $s^2$ + 28 $st$ +21 $su$

II) -8 $c^2$ + 20 $cd$

Step-by-step explanation:

umka21 [38]3 years ago

3 0

I) -7s^2+28st+21su
II) -8c^2+20cd

You might be interested in

Find the least common denominator of the fractions 2/8 and 3/5

Ierofanga [76]

Answer:

Step-by-step explanation:

2/8 = 10/40

3/5 = 24/40

3 0

3 years ago

Lucas is offered either 15% or $21 off his total shopping bill. how much would have to be spent to make the 15% option the best

vladimir1956 [14]

Let the total bill be x. We have:
<span>0.15x > 21 <-- Since 15% is 0.15 using inequality calc. x </span>>$140

4 0

3 years ago

Can someone do eight nine one and two ?

Sergeeva-Olga [200]

Answer: hello there here are your answers:

8) B multiplication property of zero

9) C additive identify

1) 8

2) -2a-7

Step-by-step explanation:

1) $\frac{3+u}8^{2} \\u=5 \\so\\ \frac{3+5}8^{2} \\3+5=8^{2} \\8^{2} =\\64 \\\\ 64/8=\\\\\\8 \\there.\\\\\\$

2) $-2(a-7)\\\\-2(a)(-7)\\\\=-2a+14\\\\\\there$

5 0

2 years ago

Need help ASAP!!!!!!!!!!!!!!!!!!!!!!!!!

il63 [147K]

Answer:

Step-by-step explanation:

ㅎㅊㄹㅇ효율ㅗㅇㅗㄴㅎㅊㅗ어ㅐ더랴ㅜㄷ훨씬ㅓ로랴류ㅑ류래ㅗㅎ7어ㅗㄹ6휴러ㅓ훠래라7하래러ㅐㅜ여ㅜㅏ

5 0

3 years ago

1. Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 c

prisoha [69]

Answer:

See explanation

Step-by-step explanation:

Among 806 people asked which is there favorite seat on a plane, 492 chose the window seat, 8 chose the middle seat, and 306 chose the aisle seat, then

$P(\text{Window seat})=\dfrac{492}{806}=\dfrac{246}{403}\\ \\P(\text{Middle seat})=\dfrac{8}{806}=\dfrac{4}{403}\\ \\P(\text{Aisle seat})=\dfrac{306}{806}=\dfrac{153}{403}$

a) One randomly selected person preferes aisle seat with probability

$\dfrac{153}{403}$

b) Two randomly selected people both prefer aisle seat (with replacement) is

$\dfrac{306}{806}\cdot \dfrac{306}{806}=\dfrac{153}{403}\cdot \dfrac{153}{403}=\dfrac{23,409}{162,409}$

c) Two randomly selected people both prefer aisle seat (without replacement) is

$\dfrac{306}{806}\cdot \dfrac{305}{805}=\dfrac{153}{403}\cdot \dfrac{61}{161}=\dfrac{9,333}{64,883}$

8 0

2 years ago

I) -7s (S-4t-3u) ii) -4c (2c-5d)​

I) -7s (S-4t-3u) ii) -4c (2c-5d)