All categories

2 years ago

Which activity did artists do during the enlightenment?

Mathematics

2 answers:

valkas [14]2 years ago

7 0

They mostly painted / drew a lot of art about the enlightenment and what was going on at that time period.

Luden [163]2 years ago

6 0

Answer:

They place more emphasis on science.

Step-by-step explanation:

The enlightenment emerged in 18th-century, which brought ideas that were deeply influenced by reason, empiricism and classics. It restructured the old Greek and Roman ideas to make new inventions, and was changing ideas due to reasoning. It was the idea behind the invention of sculpting, a new way of passing ideas or information to people more than through paintings.

Enlightenment initially started with assembling of ordinary materials by a process termed sculptural construction, did not mean exactly the same thing to everybody.

During the enlightenment, artists placed more emphasis on science.

You might be interested in

If (x,y) is a solution to the system of equations shown below, what is the product of the y-coordinates of the solutions? x^2+4y

aliina [53]

Answer:

The product of the y-coordinates of the solutions is equal to 3

Step-by-step explanation:

we have

$x^{2}+4y^{2}=40$ -----> equation A

$x+2y=8$ ------> equation B

Solve by graphing

Remember that the solutions of the system of equations are the intersection point both graphs

using a graphing tool

The solutions are the points (2,3) and (6,1)

see the attached figure

The y-coordinates of the solutions are 3 and 1

therefore

The product of the y-coordinates of the solutions is equal to

(3)(1)=3

4 0

2 years ago

Please help me do this question

bija089 [108]

Answer:

I would say three person(s).

4 0

2 years ago

Read 2 more answers

Find the center of a circle with the equation: x2 y2−32x−60y 1122=0 x 2 y 2 − 32 x − 60 y 1122 = 0

mixas84 [53]

The equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

The center of the circle exists at (16, 30).

<h3>What is the equation of a circle?</h3>

Let, the equation of a circle exists:

$$(x-h)^2 + (y-k)^2 = r^2$ , where (h, k) be the center.

We rewrite the equation and set them equal :

$$(x-h)^2 + (y-k)^2 - r^2 = x^2+y^2- 32x - 60y +1122=0$

$$x^2 - 2hx + h^2 + y^2 - 2ky + k^2 - r^2 = x^2 + y^2 - 32x - 60y +1122 = 0$

We solve for each coefficient meaning if the term on the LHS contains an x then its coefficient exists exactly as the one on the RHS containing the x or y.

-2hx = -32x

h = -32/-2

⇒ h = 16.

-2ky = -60y

k = -60/-2

⇒ k = 30.

The center of the circle exists at (16, 30).

To learn more about center of the circle refer to:

brainly.com/question/10633821

#SPJ4

7 0

1 year ago

if a rug was 5 times as long as thia record sheet, how long would it be? measure the length of this record sheet in centimeters.

vlada-n [284]

<u>Answer: </u>

If a rug was 5 times as long as this record sheet. The length of this record sheet in centimeters is 100x centimeter

<u>Solution: </u>

Given that a rug was 5 times than the record sheet.

Let assume the length of the record sheet = x units

Then from given information,

Length of the rug = 5x units

Conversion of measure of record sheet in centimeter completely depends upon in which unit the length is given.

Suppose the given length is in meters, than need to multiply the given length by 100 to get the length in centimeter that is

x meter = $x \times 100$ = 100x cm

Conversion factor will change accordingly to the unit of given length which needs to be convert into centimeter.

4 0

2 years ago

Sooo..... can anybody help.....

Margaret [11]

V= wlh so the answer is 56.25 or 56 1/4

4 0

2 years ago

Read 2 more answers