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qaws [65]
3 years ago
7

a grocery store charges 1.25$ for every 3/4 pound of chocolate purchased. How much will the store charge a customer who purchase

s 9 pounds of chocolate?
Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Given :

A grocery store charges 1.25 $ for every 3/4 pound of chocolate purchased.

To Find :

How much will the store charge a customer who purchases 9 pounds of chocolate .

Solution :

3/4 pound store charges 1.25 $ .

Let , cost of 1 pound is x .

So ,

\dfrac{3x}{4}=1.25\\\\x=\dfrac{1.25\times 4}{3}\\\\x=1.67\ \$

Now , cost of 9 pounds chocolate is :

C=9\times 1.67\ \$\\\\C=15.03\ \$

Therefore , cost of 9 pounds chocolate is 15.03 $ .

Hence , this is the required solution .

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These are three equations and three answers.


Answers:

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Explanation:


Equation A: 20 - 4x = 12 - x + 8 - 3x

The objective is clearing the unknown, which is to isolate it in one side of the equation.

These are the steps and properties that you need to use:


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2. Use addition property of equality (add 4x on each side).

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Conclusion: you have gotten a condition that is always true, no matter the value of x, which means that the equation has infinite solutions and it is an identity.


Equation B: 5x + 4x - 3  =  24 + 8x (note that I placed the equal sign as it was missing)


1.  Combine like terms on each side:

9x - 3 = 24 + 8x


2. Subtraction property and addition propertiy of equality (subtract 8x and add + 3 on both sides)

x = 27 ↔ solution (neither contradiction nor identity)


Conclusion: the solution is x = 27.


Equation C: 5x + 6 = 2x + 6 + 3x - 15 (note that I placed the equal signs as it was missing)


1. Comitne like terms on the right side:

5x + 6 = 5x - 9


2. Subtraction property of equality (subtract 5x from each side)


6 = - 9 ↔ contradiction


Conclusion: the equation does not have a solution since the final equality is always false (a condradiction or absurd).


For your information, when the variable (x) dissapears and fhe final equality is always true (for example 0 = 0, or 20 = 20), the equation is an identity.

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