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qaws [65]
3 years ago
7

a grocery store charges 1.25$ for every 3/4 pound of chocolate purchased. How much will the store charge a customer who purchase

s 9 pounds of chocolate?
Mathematics
1 answer:
Semmy [17]3 years ago
3 0

Given :

A grocery store charges 1.25 $ for every 3/4 pound of chocolate purchased.

To Find :

How much will the store charge a customer who purchases 9 pounds of chocolate .

Solution :

3/4 pound store charges 1.25 $ .

Let , cost of 1 pound is x .

So ,

\dfrac{3x}{4}=1.25\\\\x=\dfrac{1.25\times 4}{3}\\\\x=1.67\ \$

Now , cost of 9 pounds chocolate is :

C=9\times 1.67\ \$\\\\C=15.03\ \$

Therefore , cost of 9 pounds chocolate is 15.03 $ .

Hence , this is the required solution .

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3 years ago
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Xelga [282]

Answer:

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Step-by-step explanation:

We want to prove algebraically that:

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We use the relations

{r}^{2}  =  {x}^{2}  +  {y}^{2}

and

y = r \sin \theta

Before we substitute, let us rewrite the equation to get:

r(2 + 2 \sin \theta) = 10

Or

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Expand :

r+  r\sin \theta= 5

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\sqrt{ {x}^{2}  +  {y}^{2} }  + y = 5

This means that:

\sqrt{ {x}^{2}  +  {y}^{2} }=5 - y

Square:

{x}^{2}  +  {y}^{2} =(5 - y)^{2}

Expand:

{x}^{2}  +  {y}^{2} =25 - 10y +  {y}^{2}

{x}^{2}  =25 - 10y

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3 years ago
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8 0
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A rectangular metal plate is measured to be 7.6cm long and 3.1cm wide, both correct to one decimal place.
ElenaW [278]

Answer:

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The upper bound of the area is the area calculated when we use the upper bound of the length and the upper bound of the widht.

Remember that the area for a rectangle of length L and width W, is:

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Then the upper bound of the area is:

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Answer:

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P.S. hope it helped. If you have any questions, I'll be glad to answer them❤

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