Answer:
48 mph
Step-by-step explanation:
First we need to find the distance from Elkhart to Chicago. Toledo to Elkhart is 136 miles and Toledo to Chicago 244 miles.
So the distance from Elkhart to Chicago can be calculated, since Chicago is farther from Toledo than Elkhart, as: distance(Toledo to Chicago) - distance(Toledo to Elkhart). These distances are given in the problem, so the distance from Elkhat to Chicago is: 244 miles - 136 miles = 108 miles.
This problem basically wants to know the slowest you can be yet still ariving on time. If you are the minimum speed, you will arrive in Chicago exactly at 10:30 A.M. So you have 2 hours and 15 minutes(10:30 A.M - 8.15A.M.) to drive 108 miles.
15 minutes is a fourth of a hour, so you have 2.25hours to go through 108 miles.
The minimum speed you must maintain is 108mph/2.25h = 48mph.
Answer:
27 feet.
Step-by-step explanation:
Graph the quadratic equation, then find the point on the graph which aligns with x=3. Y would equal 27.
Answer:
4
Step-by-step explanation:
-2x- 4 + 5x = 8
Collect like terms
-2x + 5x = 8 +4( when a variable crosses over equality sign it becomes either negative or positive depending on the sign)
3x = 12
Divide via by coefficient of x
X = 12/3
= 4
Answer: 6x^2
Step-by-step explanation:
Answer:
the area would be 36(pi) since you can't find out the exact value of pi (22/7) and where it would terminate so thats the most exact answer you can get. The circumference would be
Step-by-step explanation:
12/2 = 6
Area = (pi)radius^2
6^2 = 36
36(pi)
Circumference: (pi)d
12(pi)
For approximate area you multiply r^2 by 3.14
For approximate circumference you multiply diameter by 3.14
