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Karolina [17]
3 years ago
10

Solve the formula for R. P=R-C

Mathematics
1 answer:
Dimas [21]3 years ago
8 0

Answer:

R=P+C

Step-by-step explanation:

These ones are really simple. To solve these you just need to get a certain value by itself and in this case, it is R. To solve this just add C because it is negative and make sure to add it to both sides and there's your answer.

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Helpppppppppppppppppp​
tekilochka [14]

Answer:

5x + y = -48

Step-by-step explanation:

(y + 3)/(x + 9) =m

=> y + 3 = -5x -45

=> 5x + y + 48 = 0

4 0
3 years ago
Anyone found this answer for this question?
Marianna [84]

Answer:

Where is the question

6 0
3 years ago
What would you have to do to change 10 cubic feet into cubic inches?
Alina [70]

A. Divide by 46,656

B. Multiply by 1,728

C. Divide by 1,728

D. Multiply by 46,656

THE ANSWER IS B MULTIPLY BY 1,728


5 0
3 years ago
-1 1/2 + (-1 1/2 <br> i need help
kirza4 [7]
-3
When there are two negative be added your answer will always be negative. In this case add the ones(2) and then add the 1/2s(1) and then add the two. For this you’ll get 3 but just add the negative sign.
6 0
3 years ago
Let V be the event that a computer contains a virus, and let W be the event that a computer contains a worm. Suppose P(V) = 0.17
ArbitrLikvidat [17]

Answer: 0.82

Step-by-step explanation:

The probability of the computer not containing neither a virus nor a worm is expressed as P(V^{C}∩W^{C}) , where P(V^{C}) is the probability that the event V doesn't happen and P(W^{C}) is the probability that the event W doesn't happen.

P(V^{C})= 1-P(V) = 1-0.17 = 0.83

P(W^{C})=1-P(W) = 1-0.05 = 0.95

Since V^{C} and W^{C} aren't mutually exclusive events, then:

P(V^{C}∪W^{C}) = P(V^{C}) + P(W^{C}) - P(V^{C}∩W^{C})

Isolating the probability that interests us:

P(V^{C}∩W^{C})= P(V^{C}) + P(W^{C}) - P(V^{C}∪W^{C})

Where P(V^{C}∪W^{C}) = 1 - 0.04 = 0.96

Finally:

P(V^{C}∩W^{C}) = 0.83 + 0.95 - 0.96 = 0.82

5 0
3 years ago
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