Answer:
a) (-4, 5)
b) (4, -5)
Step-by-step explanation:
Just reverse the signs or use desmos as a better example.
Answer: i'm pretty sure the only answer that applies is the last one.
Good luck!
Answer:
A, and D
Step-by-step explanation:
A works because when you multiply like bases, you add exponents, so we have...
5^7*5^-4 = 5^(7+(-4)) = 5^(7 -4) = 5^3
B doesn't work because when you divide like bases, you subtract the exponent of the denominator from the exponent of the denominator...
5^12/5^4 = 5^(12 - 4) = 5^8
C doesn't work because there is addition.
5 + 5² = 5 + 25 = 30, and 5³ = 125
D works because 5^0 = 1, so we have
5^0(5^3) = 1(5^3) = 5^3
E doesn't work because there is subtraction...
5^3 - 5^0 = 5^3 - 1 = 124
Considering the slope of the lines, it is found that the lines going through the points are neither parallel nor perpendicular.
<h3>When are lines parallel, perpendicular or neither?</h3>
The slope, given by <u>change in y divided by change in x</u>, determines if the lines are parallel, perpendicular, or neither, as follows:
- If they are equal, the lines are parallel.
- If their multiplication is of -1, they are perpendicular.
- Otherwise, they are neither.
In this problem, the slopes are given as follows:
- m1 = (5 - 3)/(-2 - 8) = -2/10 = -1/5 = -0.2.
- m2 = (-10 - (-5))/(-1 -(-2)) = -5/1 = -5.
The multiplication is of 1, not -1, hence they are neither parallel nor perpendicular.
More can be learned about the slope of a line at brainly.com/question/12207360
#SPJ1
Answer:
A. P( 2∪3∪1 )=1/2
B. P( 2∪3∪4∪5∪6 )= 13/16
Step-by-step explanation:
A. At first we need to get all the information that we can from the question, so we focus on the probabilities given P(2∪3∪5)=1/2 and P(4∪5∪6)=1/2 and we need to use P(5)=3/16.
Notice that when you have a dice, it´s impossible to get two values at the same try. Because of this and the property of probability for events:
P(2∪3∪5)=P(2) + P(3) + P(5) - P(2∩3)(=0) - P(3∩5)(=0) - P(2∩5)(=0) + P(2∩3∩5)(=0)
P(2∪3∪5)=P(2) + P(3) + P(5)
1/2=P(2) + P(3) + 3/16
P(2)+P(3)=5/16
If we do the same with P(4∪5∪6), we get:
P(4)+P(6)=5/16
Now, with this new information we can find P(1):
P(1)= 1 - P(2∪3∪4∪5∪6)
P(1)= 1 - (P(2) + P(3) + P(4) + P(5) + P(6)) (The probability of two of them happening at the same time is zero)
P(1)= 1 - (5/16 + 5/16 + 3/16)
P(1)= 1 - 13/16
P(1)= 3/16
And with it, we can find P(2∪3∪1):
P(2∪3∪1)=P(2)+P(3)+P(1)
P(2∪3∪1)=5/16+3/16
P(2∪3∪1)=1/2
B. Notice if you want to roll anything but a 1, then the probability you are looking for is "P(2∪3∪4∪5∪6)" but we found that in part A
P(2∪3∪4∪5∪6)=13/16
