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ZanzabumX [31]
3 years ago
11

Evaluate composite functions

Mathematics
1 answer:
Vlada [557]3 years ago
5 0

Answer:

2

Step-by-step explanation:

Step 1: Write out equation g(f(a))

1/√a

Step 2: Plug in 0.25 for <em>a</em>

1/√0.25

You answer should be 2

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Add and write the fraction or mixed number in its simplest form 2/5+1/4+7/10=
frez [133]

Answer:

1   7/20   mixed= 27/20

Step-by-step explanation:

4 0
3 years ago
Choose the kind(s) of symmetry. (Select all that apply.) F point line plane none
hram777 [196]

the kind(s) of symmetry. (Select all that apply.) F point line plane none is given below

Step-by-step explanation:

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4 0
4 years ago
Read 2 more answers
Please answer help is need.<br> attach below
Serjik [45]

Answer:

it should be 1/6 as there are six sides but only one 1.

Step-by-step explanation:

8 0
2 years ago
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Solve using a system of equations. Tickets to a local movie were sold at $6.00 for adults and $4.50 for students. If 110 tickets
Marrrta [24]

Answer:

The number of adults tickets is 80 and the number of students tickets is 30

Step-by-step explanation:

Given as :

The tickets price for adults = $6.00

The tickets price for students = $4.50

Total number tickets were sold = 110

Total Price of 110 tickets = $615.00

Now,

Let The number of adults tickets sold = A

The number of students tickets sold = S

So, according to question

          A + S =  110

And   6 A + 4.5 S = 615

Or,   6 A + 6 S =  660            .....1

       6 A + 4.5 S = 615            ......2

Solving the equations

( 6 A + 6 S ) - ( 6 A + 4.5 S ) = 660 - 615

Or,  ( 6 A - 6 A ) ( 6 S - 4.5 S ) = 45

or,  ( 6 S - 4.5 S ) = 45

or,   1.5 S = 45

∴    S = \frac{45}{1.5}

I,e  S = 30

Put the value of S in eq 1

So,  6 A + 6 × 30 =  660

Or,  6 A = 660 - 180

Or  6 A = 480

∴   A = \frac{480}{6}

I.e A = 80

Hence The number of adults tickets is 80 and the number of students tickets is 30   .     Answer

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3 years ago
Find the range and interquartille range for 13 12 15, 17, and 9,
igor_vitrenko [27]

thse is the answer goog luck

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