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ivolga24 [154]
3 years ago
6

Help pleaseee easy math with red blue cards

Mathematics
1 answer:
anygoal [31]3 years ago
8 0
Your answer is 48! :)
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Which of the pairs of angles are vertical angles and thus congruent? ∠A and ∠G ∠A and ∠B ∠C and ∠F ∠D and ∠H
r-ruslan [8.4K]

Answer:

∠A and ∠G is the pair of vertical angles.

Step-by-step explanation:

From the figure attached,

Two lines 'm' and 'n' are two parallel lines. These lines intersect a horizontal line 'l'.

Since, "Pair of opposite angles formed at the point of intersection are the vertical angles and equal in measure."

Therefore, Opposite angles ∠A ≅ ∠G, ∠B ≅ ∠H, ∠C ≅ ∠E and ∠D ∠F are the vertical angles.

From the given options,

∠A and ∠G is the pair representing the pair of vertical angles and thus congruent.

5 0
2 years ago
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The booster club needs to raise at least $7000 for new football uniforms
HACTEHA [7]
There is not alot information to answer the question.
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3 years ago
Match each equation to its solution.
astra-53 [7]
Good job you got it right! But others won’t be able to find it because you have a basic writing for it. Next time put the actual equations on so others can find it!
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3 years ago
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What is 607/100 as a percent?
777dan777 [17]


607 / 100 = 6.07

6.07 = decimal form

6.07 * 100 = 607%

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2 years ago
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Complete the table of values for y=2xsquared+x
hodyreva [135]

The solution of y= 2x^{2} +x given as:

x:   0      1       2       3

y:   0      3      10      21

<h3>What is Linear Equation?</h3>

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order (linear) term, where m is the slope and b is the y-intercept.

Given function is:

y= 2x^{2} +x

For finding the solution of above expression, take value of x and solve for y.

  • If x=0

y= 2(0)+0

y=0

  • If x=1,

y= 2(1)^{2} +1= 3

  • If x=2

y=2(2)^{2} +2=10

  • If x=3

y= 2(3)^{2} +3=21

The required table is:

x:   0      1       2       3

y:   0      3      10      21

Learn more about linear equation here:

brainly.com/question/488051

#SPJ1

8 0
2 years ago
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