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Dovator [93]
3 years ago
9

The following work represents an attempt to find the equation of the parabola which has a vertex of (0, 0) and passes through th

e point (1, 3). Is the work correct? If not, what is the error?
y=a(x-h)^2+k
0=a(0-1)^2+3
-3=a


y=a(x-h)2+k
y=-3(x)^2
y=-3x^2





A.
The equation is correct.
B.
a = –3 should have been a = 9.
C.
0=a(0-1)^2+3 should have been 3=a(1-0)^2+0
D.
-3x^2 should have been 23x^2 + 3.x
Mathematics
2 answers:
Anastaziya [24]3 years ago
7 0
The answer to your problem is b
larisa [96]3 years ago
3 0
The answer is (C) 0=a(0-1)^2+3 should have been3=a(1-0)^2=0

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