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LiRa [457]
3 years ago
5

Please help!!!!!!!!!!!!!!!!!! -3x+2 less than 8

Mathematics
1 answer:
sleet_krkn [62]3 years ago
7 0
-3x+2 < 8
-2 -2
-3 /-3x <6/-3
x >-2

So x>-2
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A company has 14 employees with a salary of ​$21,000​, 11 employees with a salary of ​$22,800​, 17 employees with a salary of ​$
kodGreya [7K]

Answer:

27525.4902

Step-by-step explanation:

First need to add the total number of employees:

14+11+17+3+5+1=51

Now multiply the salary for each number of employees then add to have the total:

14x21000+11x22800+17x24800+3x32200+5x38500+1x148300= 1403800

Now to obtain the mean value just divide the total salary by the total number of employees:

1403800/51= 27525.4902

the mean salary is $27,525.49

5 0
4 years ago
A town’s population increases at a rate of 2.3% every year. The current population is 7,500 people. Which equation models this s
ruslelena [56]

Answer:

7500 ( 1.023 ) ^(x)

Step-by-step explanation:

x is the number of years that go by

3 0
3 years ago
Read 2 more answers
What is the total area of the regions between the curves y = 6x2 − 18x and y = −6x from x = 1 to x=3?.
kvasek [131]

Using integration, it is found that the area between the two curves is of 22 square units.

<h3>What is the area between two curves?</h3>

The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:

A = \int_{x = a}^{x = b} |f(x) - g(x)| dx

In this problem, we have that:

f(x) = 6x^2 - 18x, g(x) = -6x, a = 1, b = 3.

Hence, the area is:

A = \int_{1}^3 |6x^2 - 12x| dx

A = |x^3 - 6x^2|_{x = 1}^{x = 3}

Applying the Fundamental Theorem of Calculus:

A = |3^3 - 54 - 1^3 + 6|

A = 22

The area between the two curves is of 22 square units.

More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870

8 0
3 years ago
I need help with 6 and 7 please
PolarNik [594]
For number 6 its A. 4
For number 7 its B. -2/5
7 0
3 years ago
Which operation could we perform in order to find the number of milliseconds in a year? 60 * 60 * 24 * 7 * 365 1000 * 60 * 60 *
Tom [10]
Use the following abbreviations:
y = year,
d = day,
h = hour,
min = minute,
s = second,
ms = millisecond.

Then
1 \, y = (1 \, y)*(365 \,  \frac{d}{y} )*(24 \,  \frac{h}{d} )*(60 \,  \frac{min}{h} )*(60 \,  \frac{s}{min} )*(1000 \,  \frac{ms}{s} )

Therefore, the correct calculation is
1000 * 60 * 60 * 24 * 365

Answer: 1000 * 60 * 60 * 24 * 365

4 0
3 years ago
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