1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Lena [83]
3 years ago
8

What is 6(5−8v)+12=−54

Mathematics
2 answers:
zlopas [31]3 years ago
7 0

Answer: v = 2

Step-by-step explanation:

30-48v+12 = -54

-48v = -54-30-12

\frac{-48v}{-48} = \frac{-96}{-48}

v = 2

marissa [1.9K]3 years ago
6 0

Answer:

2

Step-by-step explanation:

6(5−8v)+12=−54

Divide through by 6, we have

5 — 8v + 2 = — 9

Collect like terms

— 8v = —9 — 2 — 5

—8v = — 16

Divide both side by the coefficient of v i.e —8

v = — 16/ —8

v = 2

You might be interested in
PLS ANSWER ASAP 30 POINTS!!! CHECK PHOTO! WILL MARK BRAINLIEST TO WHO ANSWERS
Sveta_85 [38]

I'll do Problem 8 to get you started

a = 4 and c = 7 are the two given sides

Use these values in the pythagorean theorem to find side b

a^2 + b^2 = c^2\\\\4^2 + b^2 = 7^2\\\\16 + b^2 = 49\\\\b^2 = 49 - 16\\\\b^2 = 33\\\\b = \sqrt{33}\\\\

With respect to reference angle A, we have:

  • opposite side = a = 4
  • adjacent side = b = \sqrt{33}
  • hypotenuse = c = 7

Now let's compute the 6 trig ratios for the angle A.

We'll start with the sine ratio which is opposite over hypotenuse.

\sin(\text{angle}) = \frac{\text{opposite}}{\text{hypotenuse}}\\\\\sin(A) = \frac{a}{c}\\\\\sin(A) = \frac{4}{7}\\\\

Then cosine which is adjacent over hypotenuse

\cos(\text{angle}) = \frac{\text{adjacent}}{\text{hypotenuse}}\\\\\cos(A) = \frac{b}{c}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\

Tangent is the ratio of opposite over adjacent

\tan(\text{angle}) = \frac{\text{opposite}}{\text{adjacent}}\\\\\tan(A) = \frac{a}{b}\\\\\tan(A) = \frac{4}{\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{\sqrt{33}*\sqrt{33}}\\\\\tan(A) = \frac{4\sqrt{33}}{(\sqrt{33})^2}\\\\\tan(A) = \frac{4\sqrt{33}}{33}\\\\

Rationalizing the denominator may be optional, so I would ask your teacher for clarification.

So far we've taken care of 3 trig functions. The remaining 3 are reciprocals of the ones mentioned so far.

  • cosecant, abbreviated as csc, is the reciprocal of sine
  • secant, abbreviated as sec, is the reciprocal of cosine
  • cotangent, abbreviated as cot, is the reciprocal of tangent

So we'll flip the fraction of each like so:

\csc(\text{angle}) = \frac{\text{hypotenuse}}{\text{opposite}} \ \text{ ... reciprocal of sine}\\\\\csc(A) = \frac{c}{a}\\\\\csc(A) = \frac{7}{4}\\\\\sec(\text{angle}) = \frac{\text{hypotenuse}}{\text{adjacent}} \ \text{ ... reciprocal of cosine}\\\\\sec(A) = \frac{c}{b}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(\text{angle}) = \frac{\text{adjacent}}{\text{opposite}} \ \text{  ... reciprocal of tangent}\\\\\cot(A) = \frac{b}{a}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

------------------------------------------------------

Summary:

The missing side is b = \sqrt{33}

The 6 trig functions have these results

\sin(A) = \frac{4}{7}\\\\\cos(A) = \frac{\sqrt{33}}{7}\\\\\tan(A) = \frac{4}{\sqrt{33}} = \frac{4\sqrt{33}}{33}\\\\\csc(A) = \frac{7}{4}\\\\\sec(A) = \frac{7}{\sqrt{33}} = \frac{7\sqrt{33}}{33}\\\\\cot(A) = \frac{\sqrt{33}}{4}\\\\

Rationalizing the denominator may be optional, but I would ask your teacher to be sure.

7 0
1 year ago
What is the answer to the question
S_A_V [24]

The equation of the parallel line is y = –2x – 11.

Solution:

Given equation of the line is y = –2x – 5.

Slope of this line is (m_1) = –2

To write the equation parallel to this line and passes through (–4, –3).

<em>If two lines are parallel, then they have the same slope.</em>

\Rightarrow m_1=m_2

\Rightarrow m_2 =-2

<u>Point-slope formula:</u>

y-y_1=m(x-x_1)

Substitute the given values in the formula, we get

y-(-3)=-2(x-(-4))

y+3=-2(x+4)

y+3=-2x-8

Subtract 3 from both sides of the equation.

y+3-3=-2x-8-3

y=-2x-11

Hence the equation of the parallel line is y = –2x – 11.

5 0
3 years ago
Which of the following is true of the values of x and y in the diagram below?
belka [17]

Answer: y/x = 1

Step-by-step explanation:

It was on quizlet

8 0
3 years ago
What is the lateral area of a rectangular prism with length of 4in width of 5in and height of 15in
pav-90 [236]
300 cubic in. I think
7 0
3 years ago
Find the distance between the points (6,5√5) and (4,3√2).<br> 2, 2√2, 2√3
FromTheMoon [43]

Answer:

D=\sqrt{(147-30\sqrt{10}}

Step-by-step explanation:

Here we are required to find the distance between two coordinates. We will use the distance formula to find the distance

The distance formula is given as

D=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

Here we are given two coordinates as

(6,5\sqrt{5} ) , (4,3\sqrt{2} )

Substituting these values in the Distance formula given above we get

D=\sqrt{(6-4)^2+(5\sqrt{5} -3\sqrt{2}) ^2}

D=\sqrt{(2)^2+(5\sqrt{5})^2+(3\sqrt{2})^2-2*5\sqrt{5}*3\sqrt{2}}\\

D=\sqrt{4+125+18-2*15\sqrt{10}}\\D=\sqrt{147-30\sqrt{10}}\\

Hence this is our answer

6 0
3 years ago
Other questions:
  • A pizza shop offers nine toppings. No topping is used more than once. What is the probability that the toppings on a tree toppin
    11·1 answer
  • the hypotenuse and a side of a right angled triangle are 13cm and5cm respectively. fined the length of the third side​
    14·2 answers
  • Find the area of the regular hexagon
    7·2 answers
  • Solve for the variable in 7/28=25/x
    9·1 answer
  • Solve for s<br> -24-6s=-42
    13·1 answer
  • Solve 90x = 81+25x^2​
    8·1 answer
  • Please help me asap ​
    14·1 answer
  • Frank decided to keep track of his sleep using a fitness tracker. He was surprised to
    9·1 answer
  • What are the like terms on the left side of the equation?
    10·2 answers
  • Many poker games start with each player being dealt five cards, called the player's "hand". Remember, there are 52 cards in a st
    14·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!