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3 years ago

P(x) = 3x - 7; Q(x) = -4x + 3

Mathematics

1 answer:

bulgar [2K]3 years ago

8 0

Answer:

qasdddddfghjklkmnbvcxzaqwertyuioikjhgbvfcxdgfcgvhgyjfthdgfcvnbhnjkhbjgcfd b

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Derrick's Dog Sitting and Darlene's Dog Sitting are competing for new business. Derrick's Dog Sitting charges $12 plus $7 per ho

Juli2301 [7.4K]

Answer:

16+9x=20+7x Derrick's dog service is more economical

8 0

3 years ago

Read 2 more answers

A 16-ounce bottle of shampoo costs $4.69. What is the price per ounce, rounded to the nearest cent? $0.29 $0.34 $2.93 $3.41

ser-zykov [4K]

<h3>Answer: Choice A) 0.29 dollars</h3>

Work Shown:

16 ounces = 4.69 dollars

16/16 ounces = 4.69/16 dollars .... divide both sides by 16

1 ounce = 0.293125 dollars

1 ounce = 0.29 dollars .... rounding to the nearest cent

5 0

3 years ago

Read 2 more answers

Find e^cos(2+3i) as a complex number expressed in Cartesian form.

ozzi

Answer:

The complex number $e^{\cos(2+31)} = \exp(\cos(2+3i))$ has Cartesian form

$\exp\left(\cosh 3\cos 2\right)\cos(\sinh 3\sin 2)-i\exp\left(\cosh 3\cos 2\right)\sin(\sinh 3\sin 2)$ .

Step-by-step explanation:

First, we need to recall the definition of $\cos z$ when $z$ is a complex number:

$\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}$ .

Then,

$\cos(2+3i) = \frac{e^{i(2+31)} + e^{-i(2+31)}}{2} = \frac{e^{2i-3}+e^{-2i+3}}{2}$ . (I)

Now, recall the definition of the complex exponential:

$e^{z}=e^{x+iy} = e^x(\cos y +i\sin y)$ .

So,

$e^{2i-3} = e^{-3}(\cos 2+i\sin 2)$

$e^{-2i+3} = e^{3}(\cos 2-i\sin 2)$ (we use that $\sin(-y)=-\sin y)$ .

Thus,

$e^{2i-3}+e^{-2i+3} = e^{-3}\cos 2+ie^{-3}\sin 2 + e^{3}\cos 2-ie^{3}\sin 2)$

Now we group conveniently in the above expression:

$e^{2i-3}+e^{-2i+3} = (e^{-3}+e^{3})\cos 2 + i(e^{-3}-e^{3})\sin 2$ .

Now, substituting this equality in (I) we get

$\cos(2+3i) = \frac{e^{-3}+e^{3}}{2}\cos 2 -i\frac{e^{3}-e^{-3}}{2}\sin 2 = \cosh 3\cos 2-i\sinh 3\sin 2$ .

Thus,

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)$

$\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right]$ .

5 0

3 years ago

Need help with this question. I tried simplifying the radical, but apparently it’s not the answer

sesenic [268]

Answer:

-1/5+(√3)/20i or -0.2+0.05√3i

Step-by-step explanation:

$\dfrac{-8+\sqrt{-12}}{40}=-\dfrac{8}{40}+\dfrac{2\sqrt{3}i}{40}=\boxed{-\dfrac{1}{5}+\dfrac{1}{20}\sqrt{3}\,i=-0.2+0.05\sqrt{3}\,i}$

_____

<em>Comment on answer form</em>

Satisfying the input format requirements of a computer is always problematic. One never knows if fractions or decimals are preferred, whether radicals must be simplified, and so on. If no clues are offered by general instructions, other questions, or previous experience, then it might be useful to consult your instructor.

4 0

3 years ago

Which expression is 1/2 as large as 486-466

m_a_m_a [10]

Answer: 20-10

Step-by-step explanation: 486-466 is 20. Half of 20 is 10. Any expression that equals ten is 1/2 as large as 486-466.

4 0

3 years ago