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Anna35 [415]
3 years ago
13

How do you find the area?

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

• First attachment's graph is correct

• Second attachment, the area is approximately 8.6

Step-by-step explanation:

Remember that the area between two curves is defined as the following:

\mathrm{The\:area\:between\:curves\:is\:the\:area\:between\:curve\:f(x)\:and\:curve\:g(x)\:on\:interval\:[a,b]} :\\A=\int _a^b|f\left(x\right)-g\left(x\right)|dx

We are given the curves y = 7cos(2x), and y = 7 - 7cos(2x) on interval [0, π/2]. Therefore, applying the area formula, we have the solve the following integral:

\int _0^{\frac{\pi }{2}}\left|7\cos \left(2x\right)-\left(7-7\cos \left(2x\right)\right)\right|dx

From now on take a look at the attachment. It shows how to solve the integral, and it's exact value. The area is not 9.727 as you entered, it is approximately 8.6. Your graph however was accurate, but there can be no work shown for that as it's much easier to use a graphing calculator.

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3 years ago
Help with Another Pre Calculus Question
swat32

The last  equation h(x) = 2x+4/x+1.

<h3>What is a graph?</h3>

The pictorial representation of quantities and how the increase or decrease in one affects the other.

Analysis:

The graph cuts the x-axis and y-axis at (-2, 0) and(0, -4) respectively.

gradient of the curve = y2 - y1/x2 - x1 = -4-0/0--2 = -4/2 = -2.

The equation with a gradient equal to -2 is, h(x) = 2x+4/x+1

differentiating the equation by quotient rule,

u = 2x+4, du/dx = 2, v = x+1 dv/dx = 1

dy/dx = \frac{(x+1)(2) - (2x+4)(1)}{(x+1)^{2} } = \frac{-2}{(x+1)^{2} }

When x = -2, dy/dx = -2

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Learn more about parabolic curves: brainly.com/question/12896871

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2 years ago
PLEASE HELP<br> 8m+4n+7m-2n<br> 1. 17mn<br> 2. 15m+2n<br> 3. m+2n<br> 4. 15m+6n
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3 years ago
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algol13
<h3><u>Explanation</u></h3>
  • Given the equation.

10 - d =  - 34 - 5d

  • Solve the equation for d-term.

Because we cannot subtract or add up constants and variables, we simply move the same variable term to the same side and constant term to the same constant side.

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  • Answer Check

Substitute d = -11 in the equation.

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The equation is true for d = -11.

<h3><u>Answer</u></h3>

<u>\large \boxed{d =  - 11}</u>

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3 years ago
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