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Anna35 [415]
3 years ago
13

How do you find the area?

Mathematics
1 answer:
Helen [10]3 years ago
4 0

Answer:

• First attachment's graph is correct

• Second attachment, the area is approximately 8.6

Step-by-step explanation:

Remember that the area between two curves is defined as the following:

\mathrm{The\:area\:between\:curves\:is\:the\:area\:between\:curve\:f(x)\:and\:curve\:g(x)\:on\:interval\:[a,b]} :\\A=\int _a^b|f\left(x\right)-g\left(x\right)|dx

We are given the curves y = 7cos(2x), and y = 7 - 7cos(2x) on interval [0, π/2]. Therefore, applying the area formula, we have the solve the following integral:

\int _0^{\frac{\pi }{2}}\left|7\cos \left(2x\right)-\left(7-7\cos \left(2x\right)\right)\right|dx

From now on take a look at the attachment. It shows how to solve the integral, and it's exact value. The area is not 9.727 as you entered, it is approximately 8.6. Your graph however was accurate, but there can be no work shown for that as it's much easier to use a graphing calculator.

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B 5.75

Explaining:
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5 0
3 years ago
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7 0
3 years ago
Help please help me please
STatiana [176]

(x , y → (x - 5, y - 3)

the coordinates of S(1 , 5),T(1,1), U(4, 1)

the coordinates of the image are S'( - 4, 2), T'( - 4, - 2), U'( - 1 , - 2)

consider the difference in the x- coordinates of the original to the image

1 → - 4 = - 5, 1 → - 4 = - 5, 4 → - 1 = - 5

so the x- coordinate rule is x - 5

now consider the difference in the y- coordinates of the original to the image.


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so the y- coordinate rule is y - 3

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6 0
4 years ago
2x² - x + 6 is subtracted from x² + 3x - 2, the result is ​
Virty [35]

Answer:

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Step-by-step explanation:

<em>Given:</em> 2x² - x + 6 is subtracted from x² + 3x - 2

<em>Rewriting:</em> (x² + 3x - 2) - (2x² - x + 6)

<em>Distrubte negative: </em>x² + 3x - 2 - 2x² + x - 6

<em>Combine like terms:</em>  -x² + 4x - 8

<em>Answer:</em> -x² + 4x - 8

Hope this helps, have a nice day :D

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