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stiks02 [169]
3 years ago
8

Find the missing length.C= ✓ [?]26Pythagorean Theorem: a2 + b2 = c2​

Mathematics
1 answer:
mash [69]3 years ago
3 0

Answer:

c = 6.32

Step-by-step explanation:

{a}^{2} +   {b}^{2}  =  {c}^{2}  \\  {2}^{2}  +  {6}^{2}  = {c}^{2}  \\ 4 + 36 =  {c}^{2}  \\ 40 =   {c}^{2}  \\ c =  \sqrt{40}  \\ c = 6.32

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Find T5(x) : Taylor polynomial of degree 5 of the function f(x)=cos(x) at a=0 . (You need to enter function.) T5(x)= Find all va
Burka [1]

Answer:

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

The polynomial is an approximation with an error less than or equals to <em>0.002652</em> for x in the interval

[-1.113826815, 1.113826815]

Step-by-step explanation:

According to Taylor's theorem

\bf f(x)=f(0)+f'(0)x+f''(0)\displaystyle\frac{x^2}{2}+f^{(3)}(0)\displaystyle\frac{x^3}{3!}+f^{(4)}(0)\displaystyle\frac{x^4}{4!}+f^{(5)}(0)\displaystyle\frac{x^5}{5!}+R_6(x)

with

\bf R_6(x)=f^{(6)}(c)\displaystyle\frac{x^6}{6!}

for some c in the interval (-x, x)

In the particular case f

<em>f(x)=cos(x) </em>

<em> </em>

we have

\bf f'(x)=-sin(x)\\f''(x)=-cos(x)\\f^{(3)}(x)=sin(x)\\f^{(4)}(x)=cos(x)\\f^{(5)}(x)=-sin(x)\\f^{(6)}(x)=-cos(x)

therefore

\bf f'(x)=-sin(0)=0\\f''(0)=-cos(0)=-1\\f^{(3)}(0)=sin(0)=0\\f^{(4)}(0)=cos(0)=1\\f^{(5)}(0)=-sin(0)=0

and the polynomial approximation of T5(x) of cos(x) would be

\bf cos(x)\approx1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{4!}=\\\\=1-\displaystyle\frac{x^2}{2}+\displaystyle\frac{x^4}{24}

In order to find all the values of x for which this approximation is within 0.002652 of the right answer, we notice that

\bf R_6(x)=-cos(c)\displaystyle\frac{x^6}{6!}

for some c in (-x,x). So

\bf |R_6(x)|\leq|\displaystyle\frac{x^6}{6!}|=\displaystyle\frac{|x|^6}{6!}

and we must find the values of x for which

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652

Working this inequality out, we find

\bf \displaystyle\frac{|x|^6}{6!}\leq0.002652\Rightarrow |x|^6\leq1.90944\Rightarrow\\\\\Rightarrow |x|\leq\sqrt[6]{1.90944}\Rightarrow |x|\leq1.113826815

Therefore the polynomial is an approximation with an error less than or equals to 0.002652 for x in the interval

[-1.113826815, 1.113826815]

8 0
3 years ago
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DanielleElmas [232]

Answer:

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Hope this helps you

4 0
3 years ago
an item is regularly sold at $40. kala bought it at a discount of 35% off the regular price. how much did kala pay
KonstantinChe [14]

To solve this problem, we must first find the discount amount, and then subtract this amount from the total price of the item.

To find the discount amount, we must find 35% of $40. To do this, we must first convert 35% to its decimal equivalent by dividing 35/100. We do this because percentages are parts out of a total 100 percent, thus this fraction represents an equivalent value that we can multiply by other numbers. Using our knowledge that 35/100 = 0.35, we can now set up our expression:

35% of $40 (keep in mind that the word "of" refers to multiplication in math)

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To solve, we just multiply these two numbers together, which gives us 14.

This means that Kala got a discount of $14 off of the original price of $40. To find out how much she paid for it, we must subtract $14 from $40, as modeled below:

$40 - $14 = $26

Therefore, Kala paid $26 for the item.

Hope this helps!

5 0
4 years ago
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harina [27]

Answer:

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Explanation:

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3 years ago
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MAVERICK [17]

Answer: d = 40 - 5/2t; 1995

Hope it helps :)

7 0
2 years ago
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