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3 years ago

What is the solutions of the equation (4 x + 3)^2=18

Mathematics

1 answer:

tekilochka [14]3 years ago

4 0

Answer:

(4x+3)^2 = 18

16x+9=18

16x=9

Step-by-step explanation:

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inn [45]

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2 years ago

8.5cm squared = ...mm squared?<br><br> Please explain clearly

tekilochka [14]

1 centimeter = 10 milimeters.
Therefore, 8.5 centimeters squared = 85 millimeters squared.

6 0

3 years ago

Plz help with number 1

Trava [24]

In an isosceles triangle, the base angles are congruent. The third angle is called the vertex angle.

Here, the vertex angle is <A.

Therefore, m<C = m<B.

m<A = 3m<B + 20

m<A + m<B + m<C = 180

3m<B + 20 + m<B + m<B = 180

5m<B + 20 = 180

5m<B = 160

m<B = 32

m<C = m<B = 32

Answer: m<C = 32 deg

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2 years ago

The standard form of the equation of a circle with center (h, k) and radius r is __________________.

Naddika [18.5K]

$\bf \textit{equation of a circle}\\\\ 
(x-{{ h}})^2+(y-{{ k}})^2={{ r}}^2
\qquad 
\begin{array}{lllll}
center\ (&{{ h}},&{{ k}})\qquad 
radius=&{{ r}}
\end{array}$

5 0

2 years ago

2 points) Suppose w=xy+yzw=xy+yz, where x=et, y=2+sin(t)x=et, y=2+sin⁡(t), and z=2+cos(3t)z=2+cos⁡(3t). A ) Use the chain rule t

Olenka [21]

Answer:

$\frac{\partial w}{\partial t} = y(e^t) +(x+z)*(cos(t)) - 3y*sin(3t)$

Step-by-step explanation:

First, note that

$\frac{\partial x}{\partial t} = e^{t} \\\frac{\partial y}{\partial t} = cos(t)\\$

And using the chain rule in one variable

$\frac{\partial z}{\partial t} = -3sin(3t)$

Now remember that the chain rule in several variables sates that

$\frac{\partial w}{\partial t} = \frac{\partial w}{\partial x} * \frac{\partial x}{\partial t} + \frac{\partial w}{\partial y} * \frac{\partial y}{\partial t} + \frac{\partial w}{\partial z} * \frac{\partial z}{\partial t}$

Therefore the chain rule in several variables would look like this.

$\frac{\partial w}{\partial t} = y(e^t) +(x+z)*(cos(t)) - 3y*sin(3t)$

6 0

3 years ago

Read 2 more answers