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NeTakaya
3 years ago
5

Which equation best represents the line of best fit for the scatterplot?

Mathematics
1 answer:
Elena L [17]3 years ago
5 0

Answer:

The answer for this problem is

C) y = -x + 6

Step-by-step explanation:

I know this because I just did the test

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Pls answer this for me​
nekit [7.7K]

Answer:

a 166 67/100

b 20 1/4

c 829 77/100

d 664 47/50

e 208 4/25

Step-by-step explanation:

you need to find the common denominator (the number on the bottom) so for the first one when can 10 = 100 if you multiply 10 x 10 you get 100 so multiply the entire fraction by 10 and you will get 10/100 so the equation would be 381 10/100 - 214 43/100 which equals 166 67/100 then just do the same thing for the rest of them

8 0
3 years ago
I don’t know..........
SOVA2 [1]

Answer:

\frac{3}{2 }

5 0
3 years ago
Read 2 more answers
WILL MARK BRAINLIEST !! HELP ASAP
ZanzabumX [31]
What's the point of brainliest .
4 0
3 years ago
What is an inequality for x <12
natka813 [3]

X < 12                       its actually very simple , just see that the x is on one side and nothing can be moved        

4 0
3 years ago
Write 0.216 as a rational number in lowest terms
lozanna [386]

Answer:

=\frac{27}{125}

Step-by-step explanation:

0.216

\mathrm{Multiply\:and\:divide\:by\:10\:for\:every\:number\:after\:the\:decimal\:point.}

\mathrm{There\:are\:}3\mathrm{\:digits\:to\:the\:right\:of\:the\:decimal\:point,\:therefore\:multiply\:and\:divide\:by\:}1000

=\frac{0.216\cdot \:1000}{1000}

=\frac{216}{1000}

216,\:1000

\mathrm{The\:GCD\:of\:}a,\:b\mathrm{\:is\:the\:largest\:positive\:number\:that\:divides\:both\:}a\mathrm{\:and\:}b\mathrm{\:without\:a\:remainder}

2,\:3\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:3\cdot \:3\cdot \:3

2,\:5\mathrm{\:are\:all\:prime\:numbers,\:therefore\:no\:further\:factorization\:is\:possible}

=2\cdot \:2\cdot \:2\cdot \:5\cdot \:5\cdot \:5

\mathrm{The\:prime\:factors\:common\:to\:}216,\:1000\mathrm{\:are\:}

=2\cdot \:2\cdot \:2

\mathrm{Multiply\:the\:numbers:}\:2\cdot \:2\cdot \:2=8

=8

=\frac{8\cdot \:27}{8\cdot \:125}

\mathrm{Cancel\:the\:common\:factor:}\:8

=\frac{27}{125}

Hence, the correct answer is =\frac{27}{125}

6 0
2 years ago
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