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3 years ago

Which equation best represents the line of best fit for the scatterplot?

Mathematics

1 answer:

Elena L [17]3 years ago

5 0

Answer:

The answer for this problem is

C) y = -x + 6

Step-by-step explanation:

I know this because I just did the test

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Find an area of a triangle with a base of 25 feet and height of 8 feet. What’s the formula for a triangle?

marissa [1.9K]

Answer:

100 feet squared: can u plz give me the brainliest answer!!!!!!!!! plz!!!!!!!!!!!

Step-by-step explanation:

Area of triangle: base x height divided by 2.

25 x 8 = 200

200/2 = 100

Have a nice day!!!!!!!!!! :-)

4 0

3 years ago

Chandra wants to cover the entire face of the clock with a special gold foil.

Lyrx [107]

120 square inches because a circle is 360 degrees so there will be 6 60 degree sections in it and each 60 degree section needs 20 square inches to cover it so 6 x 20= 120

3 0

3 years ago

Read 2 more answers

Last month he sold 50 chickens and 30 duck fir $550. This month he sold 44 chickens and 36 ducks for $532

natali 33 [55]

Chicken - $8
Duck - $5

Work:
50c+30d=550
44c+36d=532

8 0

3 years ago

How many solutions does this<br>quadratic have?<br>f(x) = -4x2 + 12x - 9

BartSMP [9]

Answer:

one, (1.5, 0)

Step-by-step explanation:

4 0

3 years ago

An article presents a study of the failure pressures of roof panels. A sample of 15 panels constructed with 8-inch nail spacing

wariber [46]

Answer:

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

Step-by-step explanation:

From the question we are told that:

Sample size 1 $n_1=15$

Spacing 1 $s_1=8$

Mean 1 $\=x_1=8.48$

Standard deviation 1 $\sigma_1=0.96 kPa$

Sample size 2 $n_2=16$

Spacing 2 $s_2=6$

Mean 1 $\=x_1=9.93$

Standard deviation 1 $\sigma_1=1.02 kPa$

Generally the hypothesis is mathematically given as

Null $H_0:\mu_1-\mu_2$

Alternative $H_a:\mu_1\mu_2$

Generally the equation for pooled estimate is mathematically given by

$S=\sqrt{\frac{(n_1-1)\sigma_1^2+(n_2-1)\sigma_2^2}{n_1+n_2-2} }$

Therefore

$S=\sqrt{\frac{(15-1)0.96^2+(16-1)1.02^2}{15+15-2} }$

$S=0.9905$

Generally the equation for test statistics is mathematically given by

$t=\frac{\=x_1+\=x_2}{S\sqrt{\frac{1}{n _1}+\frac{1}{n_2}}}$

$t=\frac{\=8.48-9.93}{0.9905\sqrt{\frac{1}{15}+\frac{1}{15}}}$

$t=-4.00091$

Therefore From table

$P value=P(t_{15+15-2}=4.00091)$

$P value=0.00041918$

$P$

Therefore

There is sufficient evidence to conclude that six inches spacing has a higher mean failure pressure than 8 inches

Reject $H_0\ at\ 5%$ level of significance

3 0

3 years ago