Sams garden is shaped like the picture. If the area is 304 ft (squared) what would the length of the side for the rectangle be?
Please help this is my homework due tommorow
1 answer:
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Answer:
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
Step-by-step explanation:
Step 1:-
let 'x' be the length and the 'y' be the width of the rectangle
given Jenna's buys 80ft of fencing of rectangle so the perimeter of the rectangle is 2(x +y) = 80
x + y =40
y = 40 -x
now the area of the rectangle A = length X width
A = x y
substitute 'y' value in above A = x (40 - x)
A = 40 x - x^2 .....(1)
<u>Step :2</u>
now differentiating equation (1) with respective to 'x'
........(2)
<u>Find the dimensions</u>
<u></u><u></u>
40 - 2x =0
40 = 2x
x = 20
and y = 40 - x = 40 -20 =20
The dimensions are x =20 and y=20
length = 20 and breadth = 20
<u>Step 3</u>:-
we have to find maximum area
Again differentiating equation (2) with respective to 'x' we get
Now the maximum area A = x y at x =20 and y=20
A = 20 X 20 = 400
<u>Conclusion</u>:-
The dimensions are x =20 and y=20 of the garden that will maximize its area is 400
<u>verification</u>:-
The perimeter = 2(x +y) =80
2(20 +20) =80
2(40) =80
80 =80