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2 years ago

9

Sams garden is shaped like the picture. If the area is 304 ft (squared) what would the length of the side for the rectangle be?

Please help this is my homework due tommorow

1 answer:

lozanna [386]2 years ago

3 0

The answer is 76. You divide 304 by 4 and get 76.

<span>In short answer is 76.</span>

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I need help on these questions pls

Lady bird [3.3K]

3a. Megan's car has more gas
3b. 2/3=66.666% and 3/5= 60% so 6 2/3 gallons

5. 108.09-15.45= 92.64

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3 years ago

Select all of the names of this polygon.

Shalnov [3]

Trapezoid
quadrilateral
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2 years ago

Help math sucks THESE MAKE MY BRAIN DIE

Flura [38]

Answer:

A ∩ B = {1, 3, 5}

A - B = {2, 4}

Step-by-step explanation:

The given problem regards sets and set notation, a set can simply be defined as a collection of values. One is given the following information:

A = {1, 2, 3, 4, 5}

B = {1, 3, 5, 6, 9}

One is asked to find the following:

A ∩ B,

A - B

1. Solving problem 1

A ∩ B,

The symbol (∩) in set notation refers to the intersection between the two sets. It essentially asks one to find all of the terms that two sets have in common. The given sets (A) and (B) have the values ({1, 3, 5}) in common thus, the following statement can be made,

A ∩ B = {1, 3, 5}

2. Solving problem 2

A - B

Subtracting two sets is essentially taking one set, and removing the values that are shared in common with the other set. Sets (A) and (B) have the following values in common ({1, 3, 5}). Thus, when doing (A - B), one will omit the values ({1, 3, 5}) from set (A).

A - B = {2, 4}

3 0

2 years ago

The braking distance, in feet of a car a Travling at v miles per hour is given.

irakobra [83]

The braking distance is the distance the car travels before coming to a stop after the brakes are applied

a. The braking distances are as follows;

The braking distance at 25 mph, is approximately <u>63.7 ft.</u>

The braking distance at 55 mph, is approximately <u>298.35 ft.</u>

The braking distance at 85 mph, is approximately <u>708.92 ft.</u>

b. If the car takes 450 feet to brake, it was traveling with a speed of 98.211 ft./s

Reason:

The given function for the braking distance is D = 2.6 + v²/22

a. The braking distance if the car is going 25 mph is therefore;

25 mph = 36.66339 ft./s

$D = 2.6 + \dfrac{36.66339^2}{22} = 63.7 \ ft.$

At 25 mph, the braking distance is approximately <u>63.7 ft.</u>

At 55 mph, the braking distance is given as follows;

55 mph = 80.65945 ft.s

$D = 2.6 + \dfrac{80.65945^2}{22} \approx 298.35 \ ft.$

At 55 mph, the braking distance is approximately <u>298.35 ft.</u>

At 85 mph, the braking distance is given as follows;

85 mph = 124.6555 ft.s

$D = 2.6 + \dfrac{124.6555^2}{22} \approx 708.92 \ ft.$

At 85 mph, the braking distance is approximately <u>708.92 ft.</u>

b. The speed of the car when the braking distance is 450 feet is given as follows;

$450 = 2.6 + \dfrac{v^2}{22}$

v² = (450 - 2.6) × 22 = 9842.8

v = √(9842.2) ≈ 98.211 ft./s

The car was moving at v ≈ <u>98.211 ft./s</u>

Learn more here:

brainly.com/question/18591940

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1 year ago

8x-3=3x+17<br> Solve for x

Olin [163]

Answer:

x = 4

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers