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max2010maxim [7]
3 years ago
15

Suppose we have a population that does not follow the normal distribution. What minimum sample size we should select in order to

have an approximately normal distribution (symmetric)? A. more than 10% of population size . B. it is based on population standard deviation C. 20 D. 30
Mathematics
1 answer:
Pepsi [2]3 years ago
5 0

Answer:

D. 30

Step-by-step explanation:

Having a population that doesn't follow normal distribution (skewed) can still have sampling distribution that is completely normal. This fact is presented in the Central Limit Theorem.

Central Limit Theorem: states that we can have a normal distribution of sample means even if the original population doesn't follow normal distribution, we just need to take a large sample.

So how much sample size do we need?

There is no straight forward answer to this rather we have to analyse the situation closely!

1. If the population distribution is already normal then a smaller sample size would be enough to ensure normal distribution.

2. If the population distribution is very skewed than a larger number of sample size is needed to ensure normal distribution. The rule of thumb is to take sample size equal to or more than 30 to be on safer side. This is the case in this problem hence option D fits the best.

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A kitchen sink faucet streams 0.5 gallon of water in 10 seconds. A bathroom sink faucet stream 0.75 gallon of water in 18 second
Masteriza [31]

Answer:

kitchen sink faucet stream

Step-by-step explanation:

with kitchen sink faucet you fill 0.05gallons of water per second you get that by dividing 0.5 by 10

and the bathroom sink faucet does 0.041gallons of water per second you get that by dividing 0.75 by 18

7 0
3 years ago
Write an equation of the line that passes through the given points.<br> (-1,7) and (4, -8)
djverab [1.8K]

Answer:

y=-3x+4

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(-8-7)/(4-(-1))

m=-15/(4+1)

m=-15/5

m=-3

y-y1=m(x-x1)

y-7=-3(x-(-1))

y-7=-3(x+1)

y=-3x-3+7

y=-3x+4

3 0
3 years ago
A club swimming pool is 29 ft wide and 43 ft long. the club members want an exposed aggregate border in a strip of uniform width
OlgaM077 [116]
296 square <span>feet is your answer</span>
3 0
3 years ago
In general, after a group makes a reservation at a restaurant, they do not show up 20% of the time. If a restaurant has 8 reserv
sashaice [31]

Answer:

P(more than 2 don't show up)=0.2031

Step-by-step explanation:

Multiplication rule for independent events:

If two events A and B are independent then the multiplication rule state that:

P(A and B)= P(A) x P(B)

Find the probability that more than two do not show up:

The probability that the reservations at the restaurant do not show up is 0.20 (=20%) and there were 8 reservations.

P(more than 2 don't show up)= 1- P(less than or equal to 2 don't show up)

= 1-( P(none show up) +P(one don't show up)+P(two don't show up)

=1- ((0.8⁸) +₈ C₁ (0.2¹)x(0.8⁷)  +₈ C₂ (0.2²)x(0.8⁶)

=1- (0.1678 +0.3355+0.2936)= 1-0.7969

P(more than 2 don't show up)=0.2031

5 0
3 years ago
leonhard wants to place a triangular-based cabinet in the corner of his rectangle-shaped living room. the triangular base has a
Georgia [21]
The answer is x =  \frac{-7+ \sqrt{193} }{4}.

There is very similar question on Brainly, in which dimensions of the living room are given (20 feet, 30 feet).
So, knowing this, we first need to calculate how much 6% of the living room is.
The area of the living room is 600 square feet, since it is rectangle-shaped:
P = a * b = 200 feet * 30 feet = 600 square feet.

6% of 600 square feet is 36 square feet:
600 square feet : 100% = A : 6%
A = 600 * 6 / 100 = 36 square feet

The area of the triangular-based cabinet (A) is A = \frac{a*h}{2}, where a is the base, and h is the height of the triangle.
It is given:
A = 36
a = 2x + 3
h = 3x + 6

Now, let's implement this to the formula A =  \frac{a*h}{2}:
36 =  \frac{(2x+3)(3x+6)}{2}
⇒ 36*2=6 x^{2} +12x+9x+18
72=6 x^{2} +21x+18

Let's both sides divide by 3:
24=2 x^{2} +7x+6
⇒ 2 x^{2} +7x-18=0

This is the quadratic formula (a x^{2} +bx+c=0) for which
x =  \frac{-b+\sqrt{b^{2} -4ac} }{2a} or
<span>x = \frac{-b-\sqrt{b^{2} -4ac} }{2a}.
</span>We will use only <span>x = \frac{-b+\sqrt{b^{2} -4ac} }{2a}, because the length cannot have negative value.</span>


<span>From the equation 2 x^{2} +7x-18=0, we know that
</span>a = 2
b = 7
c = -18

Thus, <span> x = \frac{-7+ \sqrt{193} }{4}:
</span>x= \frac{-b+ \sqrt{ b^{2} -4ac} }{2a} = \frac{-7+ \sqrt{ (7)^{2} -4*2*(-18)} }{2*2} = \frac{-7+ \sqrt{49+144} }{4} = \frac{-7+ \sqrt{193} }{4}

4 0
3 years ago
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