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KIM [24]
3 years ago
15

Which ordered pair is the best estimate for the

Mathematics
1 answer:
k0ka [10]3 years ago
3 0
Given the pair of simultaneous equation:
y=-2/5x-2
y=5x+1
To evaluate the solution of the system of equation from the graph, we obtain the point at which the two linear equations have intersected. taking the values of x and y from the point of intersection that will be the solution of the system of linear equations. 
In our case the straight lines have intersected at the point (-0.5, -1.75). This implies that:
x=-0.5
y=-1.75
hence the answer is a] (-0.5, -1.75)
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PLS HELP ME XD, WHAT IS 1/4 x 24??
Shkiper50 [21]
1/4 x 24 is 6.

Your welcome
8 0
3 years ago
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alexdok [17]
There’s the link to this answer
8 0
3 years ago
g Minimizing the sum of the squared deviations around the line is called: predictor regression. mean squared error technique. le
Alex787 [66]

Minimizing the sum of the squared deviations around the line is called Least square estimation.

It is given that the sum of squares is around the line.

Least squares estimations minimize the sum of squared deviations around the estimated regression function. It is between observed data, on the one hand, and their expected values on the other. This is called least squares estimation because it gives the least value for the sum of squared errors. Finding the best estimates of the coefficients is often called “fitting” the model to the data, or sometimes “learning” or “training” the model.

To learn more about regression visit: brainly.com/question/14563186

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3 0
1 year ago
Simplify this expression
pishuonlain [190]

Answer:

After simplifying, the exponent of x is 33 and the exponent of y is 0

Step-by-step explanation:

For us to simplify, we bring the x base together and the y base together

Recall from the law of indices;

x^a/x^b = x^(a-b)

and x^a * x^b = x^(a + b)

We shall be applying these here

Let us bring the x terms together

we have these as;

x^8/x^14 * 1/x^-39 = x^( 8 - 14 -(-39))

= x^(8 + 39-14) = x^33

for y, we have it that;

y^-26/y^-5 * 1/y^-21

= y^(-26 -(-5) - (-21)

= y^-26 + 5 + 21 = y^0

8 0
3 years ago
Part B
Elza [17]

Answer:

copy and paste

Step-by-step explanation:

6 0
3 years ago
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