Answer:
See below in the explanation section the Matlab script to solve the problem.
Explanation:
prompt='enter the first weight w1: ';
w1=input(prompt);
wd1=double(w1);
prompt='enter the second weight w2: ';
w2=input(prompt);
wd2=double(w2);
prompt='enter the third weight w3: ';
w3=input(prompt);
wd3=double(w3);
prompt='enter the fourth weight w4: ';
w4=input(prompt);
wd4=double(w4);
prompt='enter the first weight w5: ';
w5=input(prompt);
wd5=double(w5);
x=[wd1 wd2 wd3 wd4 wd5]
format short
Answer:
Aqueous solution of ionic compounds conduct electricity while solid ionic compounds don't.
Explanation:
Ionic compound conduct electricity when liquid or in aqueous solution that is resolved in water because the ionic bonds of the compound become weak and the ions are free to move from place to place.
Ionic compounds don't conduct electricity while in solid state because the ionic bonds are to strong and ions cannot move around with lack of space for movement which makes the electric conductivity zero.
Answer:
Q=36444.11 Btu
Explanation:
Given that
Initial temperature = 60° F
Final temperature = 110° F
Specific heat of water = 0.999 Btu/lbm.R
Volume of water = 90 gallon
Mass = Volume x density
Mass ,m= 90 x 0.13 x 62.36 lbm
m=729.62 lbm
We know that sensible heat given as
Q= m Cp ΔT
Now by putting the values
Q= 729.62 x 0.999 x (110-60) Btu
Q=36444.11 Btu
