Answer:
total time = 304.21 s
Explanation:
given data
y = 50% = 0.5
n = 1.1
t = 114 s
y = 1 - exp(-kt^n)
solution
first we get here k value by given equation
y = 1 -
...........1
put here value and we get
0.5 = 1 - e^{(-k(114)^{1.1})}
solve it we get
k = 0.003786 = 37.86 ×
so here
y = 1 -
1 - y =
take ln both side
ln(1-y) = -k ×
so
t =
.............2
now we will put the value of y = 87% in equation with k and find out t
t = ![\sqrt[1.1]{-\frac{ln(1-0.87)}{37.86*10^{-4}}}](https://tex.z-dn.net/?f=%5Csqrt%5B1.1%5D%7B-%5Cfrac%7Bln%281-0.87%29%7D%7B37.86%2A10%5E%7B-4%7D%7D%7D)
total time = 304.21 s
Answer:
I think 5 is passion and 6 is true I think and 7 is time management I'm pretty sure
Answer:
The rate at which water is being withdrawn from the river by the city is 57353 acre-ft/y
Explanation:
Please look at the solution in the attached Word file
Johnjjjjjjhhhhhhhhjjjjjjjjjjj
Answer:
kinematic viscosity is 0.0149 ft²/s
Explanation:
given data
specific gravity S = 0.94
density ρ = 0.94 × 1000
viscosity μ = 13 Poise = 1.3 Pa-sec
we know 1 poise = 0.1 pas
to find out
kinematic viscosity
solution
we will apply here Kinematic viscosity formula that is
kinematic viscosity =
..................1
put here value in equation 1
and here ρ is density and μ is viscosity
kinematic viscosity =
kinematic viscosity = 1.382978 ×
m³/s
so kinematic viscosity is 0.0149 ft²/s