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dolphi86 [110]
3 years ago
11

Another sigma notation question. Please check. Hopefully I did this one correctly!

Mathematics
1 answer:
Neko [114]3 years ago
8 0

Answer:

Your answer is correct.  The series is a geometric series with common ratio -1/4 and first term 40.  So each term is:

an = 40 (-1/4)^(n−1)

So the sum of the first 10 terms is:

∑(n=1 to 10) [ 40 (-1/4)^(n−1) ]

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Given a standard form linear equation 33 - 4y = 12​
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5 1/4

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3 years ago
What is the simplified expression for,
Nostrana [21]

Here are a few rules you need to know for this equation:

  • Multiplying exponents of the same base: x^m\times x^n=x^{m+n}
  • Dividing exponents of the same base: \frac{x^m}{x^n}=x^{m-n}
  • Turning a negative exponent to a positive one: x^{-m}=\frac{1}{x^m};\frac{1}{x^{-m}}=x^m

So this is our algebraic expression: \frac{3^{-4}\times 2^3\times 3^2}{2^4\times 3^{-3}}

Firstly, multiply 3^-4 and 3^2: \frac{3^{-4+2}\times 2^3}{2^4\times 3^{-3}}=\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}

Next, divide:

\frac{3^{-2}\times 2^3}{2^4\times 3^{-3}}=3^{-2-(-3)}2^{3-4}=3^12^{-1}

Next, turn the negative exponent into a positive one: 3^12^{-1}= \frac{3}{2}

<u>Your final answer is 3/2, or 1.5.</u>

6 0
3 years ago
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