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slava [35]
2 years ago
14

Order from least to greatest 14,20,15,10,7,12,14,15,10

Mathematics
2 answers:
Nikolay [14]2 years ago
8 0

Answer:

7, 10, 10, 12, 14, 14, 15, 15, 20

Step-by-step explanation:

The numbers are in order from least to greatest. With this order, you can also easily calculate the mean, median, range and mode if necessary.

defon2 years ago
3 0

Answer:

7 10 10 12 14 14 15 15 20

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What is 26/4, 6.45, 6 2/5, and 50/8 in order from least to greatest?
blagie [28]

26/4=6.50

6.45=6.45

6and 2/5=6.40

50/8=6.25

so it should be

least- greatest

50/8, 6 & 2/5, 6.45, 26/4

7 0
3 years ago
What is 26/15 as a whole number?
Contact [7]

Answer:

1 11/15

Step-by-step explanation:

4 0
2 years ago
Seven times the sum of 4 and some number is 42
Naddik [55]

Answer:

x=2

Step-by-step explanation:

7\times{(4+x)}=42

Divide both sides by 7:

4+x=42\div{7}\\4+x=6

Subtract 4 from both sides:

x=6-4\\x=2

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2 years ago
What the heck is happening in this picture
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Read 2 more answers
Evaluate Dx / ^ 9-8x - x2^
Solnce55 [7]
It depends on what you mean by the delimiting carats "^"...

Since you use parentheses appropriately in the answer choices, I'm going to go out on a limb here and assume something like "^x^" stands for \sqrt x.

In that case, you want to find the antiderivative,

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}

Complete the square in the denominator:

9-8x-x^2=25-(16+8x+x^2)=5^2-(x+4)^2

Now substitute x+4=5\sin y, so that \mathrm dx=5\cos y\,\mathrm dy. Then

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\int\frac{5\cos y}{\sqrt{5^2-(5\sin y)^2}}\,\mathrm dy

which simplifies to

\displaystyle\int\frac{5\cos 
y}{5\sqrt{1-\sin^2y}}\,\mathrm dy=\int\frac{\cos y}{\sqrt{\cos^2y}}\,\mathrm dy

Now, recall that \sqrt{x^2}=|x|. But we want the substitution we made to be reversible, so that

x+4=5\sin y\iff y=\sin^{-1}\left(\dfrac{x+4}5\right)

which implies that -\dfrac\pi2\le y\le\dfrac\pi2. (This is the range of the inverse sine function.)

Under these conditions, we have \cos y\ge0, which lets us reduce \sqrt{\cos^2y}=|\cos y|=\cos y. Finally,

\displaystyle\int\frac{\cos y}{\cos y}\,\mathrm dy=\int\mathrm dy=y+C

and back-substituting to get this in terms of x yields

\displaystyle\int\frac{\mathrm dx}{\sqrt{9-8x-x^2}}=\sin^{-1}\left(\frac{x+4}5\right)+C
4 0
2 years ago
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