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Marrrta [24]
3 years ago
8

In a triangle ABC, if angle B= 60° and the ratio of two sides is a: C= 2: sqrt3 + 1, then angle A=

Mathematics
2 answers:
nydimaria [60]3 years ago
4 0
I’m pretty sure the answer is 45
yawa3891 [41]3 years ago
3 0

Answer:

<em>Well, Your best answer will be is </em><em>45° </em><em>Because, Given two sides and the angle in between,  we can calculate for ∠A using the sine law: </em>

<em> </em>

<em>b / sin B = a / sin A </em>

<em> </em>

<em>2.45 / sin 60 = 2 / sin A </em>

<em> </em>

<em>sin A = 0.707 </em>

<em> </em>

<em>A = 45˚ </em>

<em> </em>

<em>Therefore the answer is letter A: 45 </em><em>Good Luck! </em>

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I make 2.5kg of popcorn and eat 750g of it while 750g of it while watching a movie . How much popcorn do i have left?
elena-14-01-66 [18.8K]

Answer:

1,75 kg

Explanation:

1 kg = 1000 g

2.5 kg = 2.5 × 1000 g = 2500 g

2500 g - 750 g = 1750 g

1750 g = 1750 ÷ 1000 kg = 1.75 kg

5 0
3 years ago
Highest common factor of 24 and 108​
Angelina_Jolie [31]

Answer:

12

Step-by-step explanation:

The factors of 24 are: 1, 2, 3, 4, 6, 8, 12, 24  

The factors of 108 are: 1, 2, 3, 4, 6, 9, 12, 18, 27, 36, 54, 108  

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4 0
2 years ago
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Mama L [17]

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7 0
2 years ago
Calculate the value for each determinant:
Sergeeva-Olga [200]

Answer:

Step-by-step explanation:

\begin{vmatrix}3 & -1\\ -3 & 4\end{vmatrix}=(3\times 4)-(-1)\times (-3)

               = 12 - 3

               = 9

\begin{vmatrix}8 & -1\\ -4 & -1\end{vmatrix}=8\times(-1)-(-1)\times(-4)

               = -8 - 4

               = -12

\begin{vmatrix}-12 & -1\\ 12 & 5\end{vmatrix}=(-12)\times(5)-(-1)\times(12)

                = -60 + 12

                = -48

\begin{vmatrix}2 & -1\\ 2 & -1\end{vmatrix}=2\times(-1)-(2)\times(-1)

            = -2 + 2

            = 0

\begin{vmatrix}0 & -1\\ 17 & 4\end{vmatrix}=0\times(4)-(-1)\times(17)

              = 17

\begin{vmatrix}1 & 0\\ 0 & 1\end{vmatrix}=1\times(1)-(0)\times(0)

          = 1

6 0
2 years ago
Read 2 more answers
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bazaltina [42]
<span>2≤x≤8</span> <span>−4≤<span>f′</span>(x)≤5</span> f is continuous in differentable on [2,8] so we know there is c btw 2 and 8 such that <span><span>f′</span>(c)=<span><span>f(8)−f(2)</span><span>/8−2</span></span></span> And we know <span>−4≤<span>f′</span>(c)≤5</span> => we have <span>−4≤ <span><span>f(8)−f(2)</span><span>/8−2</span></span> ≤<span>5</span></span>
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