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3 years ago

Can someone explain square roots to me?? I don't get them at all :/

Mathematics

2 answers:

pantera1 [17]3 years ago

7 0

The square root of a number is a number that when you multiply it by itself you get back to your number.

Example:

What is the square root of 16? You are looking for a number that when you multiply it by itself, you get 16. Try 4. 4 multiplied by itself is 4 * 4 and 4 * 4 is 16, so 4 is a square root if 16. There is another square root of 16. It is -4 since (-4) * (-4) = 16.

What is the square root of 4? 2 and -2 since 2 * 2 = 4 and (-2) * (-2) = 4.

The square roots of 9 are 3 and -3.

The square root of 0 is 0.

maw [93]3 years ago

3 0

You can think of it in terms of squares. The area of a square is 36 say. The square root in that case is the side length.

Draw yourself a square. Label one side 6. Find the area. The formula is side length times side length. 6 * 6 = 36

The root of the square is 6. I suspect your problem is more language that math. The length of the side is the square root of the area of the square.

Every square root can be thought of that way. For example the square root of 200 = 14.14

Draw a square. Label one side as 14.14. That means that square has an area of 200 units. It has a side length of 14.14. That's the square root of the area.

If you're still stuck leave a note and we'll try something else. Do you know how to find square roots on your calculator?

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Given that the function g is defined by the rule g(x)=3-2x,determine the following

Illusion [34]

Answer:

The value of g(a) is:

g(a) = 3 - 2a

Step-by-step explanation:

Given

As the function g(x) is given by

$g(x)=3-2x$

To determine

g(a) = ?

In order to determine g(a),

substitute x = a in the function g(x) = 3 - 2x

g(x) = 3 - 2x

g(a) = 3 - 2(a)

g(a) = 3 - 2a

Therefore, the value of g(a) is:

g(a) = 3 - 2a

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3 years ago

Find the value of using identities 996^2

Svetlanka [38]

Answer:

992,016

Step-by-step explanation:

${996}^{2} \\ = {(1000 - 4)}^{2} \\ = {1000}^{2} - 2 \times 1000 \times 4 + {4}^{2} \\ = 1000000 - 8000 + 16 \\ = 1000016 - 8000 \\ = 992,016 \\$

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3 years ago

Solve for j in the literal equation h-4/j

igor_vitrenko [27]

Answer:

$h - 4 \div j = 0 \\ - 4 \div j = - h \\ 4 \div j = h \\ j = 4 \div h$

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3 years ago

How to find rate of change on a table

LekaFEV [45]

Answer:

__X__l__Y_

1 l 3

5 l 6

9 l 9

13 l 12

17 l 15

21 l 18

On the right side, the numbers get larger by adding three each time. On the left side, the numbers get larger by adding 4 each time. It would be the same for any other pair of numbers when you add 4 to the left, and 3 to the right. For instance, the next pair would be (25 , 21). 25 would be the X value, and 21 would be the Y value.

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3 years ago

For integers a, b, and c, consider the linear Diophantine equation ax C by D c: Suppose integers x0 and y0 satisfy the equation;

Dmitrij [34]

Answer:

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

b. x = -8 and y = 4

Step-by-step explanation:

This question is incomplete. I will type the complete question below before giving my solution.

For integers a, b, c, consider the linear Diophantine equation

$ax+by=c$

Suppose integers x0 and yo satisfy the equation; that is,

$ax_0+by_0 = c$

what other values

$x = x_0+h$ and $y=y_0+k$

also satisfy ax + by = c? Formulate a conjecture that answers this question.

Devise some numerical examples to ground your exploration. For example, 6(-3) + 15*2 = 12.

Can you find other integers x and y such that 6x + 15y = 12?

How many other pairs of integers x and y can you find ?

Can you find infinitely many other solutions?

From the Extended Euclidean Algorithm, given any integers a and b, integers s and t can be found such that

$as+bt=gcd(a,b)$

the numbers s and t are not unique, but you only need one pair. Once s and t are found, since we are assuming that gcd(a,b) divides c, there exists an integer k such that gcd(a,b)k = c.

Multiplying as + bt = gcd(a,b) through by k you get

$a(sk) + b(tk) = gcd(a,b)k = c$

So this gives one solution, with x = sk and y = tk.

Now assuming that ax1 + by1 = c is a solution, and ax + by = c is some other solution. Taking the difference between the two, we get

$a(x_1-x) + b(y_1-y)=0$

Therefore,

$a(x_1-x) = b(y-y_1)$

This means that a divides b(y−y1), and therefore a/gcd(a,b) divides y−y1. Hence,

$y = y_1+r(\frac{a}{gcd(a, b)})$ for some integer r. Substituting into the equation

$a(x_1-x)=rb(\frac{a}{gcd(a, b)} )\\gcd(a, b)*a(x_1-x)=rba$

$x = x_1-r(\frac{b}{gcd(a, b)} )$

Thus if ax1 + by1 = c is any solution, then all solutions are of the form

$x = x_1+r(\frac{b}{gcd(a, b)} )\\y=y_1-r(\frac{a}{gcd(a, b)} )$

In order to find all integer solutions to 6x + 15y = 12

we first use the Euclidean algorithm to find gcd(15,6); the parenthetical equation is how we will use this equality after we complete the computation.

$15 = 6*2+3\\6=3*2+0$