Answer:
Step-by-step explanation:
(-1/9) /(1/3) = (1/3)/(-1) = -1/3....the common ratio of geometric sequence
the recursive rule is :
the nth term is : An =A1 × r^(n-1)
r : the common ratio
A1 ; the first term
r = -1/3 and A1 = 3
An =3 ×(-1/3)^(n-1)
Answer:
B. 8m
Step-by-step explanation:
Given:
The figure is a kite having points QRST.
It has short diagonal QS.
Long diagonal RT
Diagonal Intersect at point P.
side QR = 10m
Diagonal QS = 12m
We need to find the length of segment RP.
According Diagonal Property of kite.
It states that Diagonals of Kite perpendicularly bisects each other.
QP = PS
RP = PT
But QS = QP + PS
QS = QP + QP
QS = 2 QP
QP =
QS = 
Now In Δ QPR
m∠ P = 90° (Diagonals of a kite is perpendicular to each other)
Now by Pythagoras theorem;

Hence the Length of segment RP is 8m.
Answer:
make it so that the top side is 40 and make the sides 35
Step-by-step explanation:
I think the trick is to add the two middle terms together. (And the 2 end terms).
8 - 12x
The variable is x. The coefficient is - 12.
8 is a constant.
The coefficient always goes with a variable.
3x^2 + 2x + 5
Nothing can be combined. The leading coefficient is 3 (which goes with the greatest power of the variable x^2 in this case) and the other coefficient is 2. 5 is a constant.
length = 3234 m and width = 1614 m
let the width = w then length = 2w + 6
Perimeter = 2 ( length + width )
= 2 (2w + 6 + w ) = 2 ( 3w + 6 ) = 6w + 12
given perimeter = 9696 the equating gives
6w + 12 = 9696
subtract 12 from both sides
6w = 9696 - 12 = 9684
divide both sides by 6
w =
= 1614
width = 1614 m and length = (2 × 1614 ) + 6 = 3234 m