N-acetyltyrosine ethyl ester may likely have a higher Vmax.
<h3>How are the Km and Vmax of an enzyme and substrate related?</h3>
Km is inversely proportional enzyme affinity for substrate. The lower the Km, the higher the enzyme affinity for substrate and vice versa.
Vmax is the maximum velocity of the reaction when the enzyme is fully saturated with substrate.
Based on the Km values, chymotrypsin has higher affinity for N-acetyltyrosine ethyl ester, thus, N-acetyltyrosine ethyl ester may likely have a higher Vmax.
In conclusion, the Vmax is the maximum velocity of an enzyme-catalyzed reaction.
<em>Note that the complete question is given below:</em>
<em>The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M.</em>
<em>Which of the following substrates is likely to give a higher value for Vmax?</em>
Learn more about Km and Vmax at: brainly.com/question/16108691
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Answer:
7*2/5 it is a improper fraction
Answer:
<u>There were 6, 9, 12 and 15 children if the number of adults at the beach were 8, 12, 16 and 20.</u>
Step-by-step explanation:
After reviewing the information given for solving the question, we notice that the ratio of adults in relation with the number of children at the beach is 4:3. In that case, for finding the number of children for every specific number of adults, we do the following calculations:
1. For 8 adults: 8/4 = 2 and using the ratio 4:3, we multiply by 2 and we get that the number of children is 6.
2. For 12 adults: 12/4 = 3 and using the ratio 4:3, we multiply by 3 and we get that the number of children is 9.
3. For 16 adults: 16/4 = 4 and using the ratio 4:3, we multiply by 4 and we get that the number of children is 12.
4. For 20 adults: 20/4 = 5 and using the ratio 4:3, we multiply by 5 and we get that the number of children is 15.
<u>There were 6, 9, 12 and 15 children if the number of adults at the beach were 8, 12, 16 and 20.</u>
1, when you factor you get 6x(x^2-1)+4(x^2-1)=
