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kaheart [24]
3 years ago
7

Negative one fourths times negative six elevenths

Mathematics
1 answer:
Ipatiy [6.2K]3 years ago
3 0

You multiply fractions simply by multiplying numerators and denominators with each other:

-\dfrac{1}{4} \times \left(-\dfrac{6}{11}\right) = \dfrac{1 \times 6}{4 \times 11} = \dfrac{6}{44} = \dfrac{3}{22}

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Phoenix [80]

The multiples of 5 and 6 based on the information have been illustrated below.

<h3>How to illustrate the multiple?</h3>

It should be noted that a multiple is a number that can be divided by another number without a remainder.

Here, the multiples of 5 will be:

5 = 5, 10, 15, 20, 25, 30, 35, 40, 45, 50, 55, 60.

6 = 6, 12, 18, 24, 30, 36, 42, 48, 54, 60, ...

In this case, the multiples of the numbers have been illustrated.

Learn more about multiples on:

brainly.com/question/251701

#SPJ1

6 0
2 years ago
Which ratio forms a proportion with 9/15 ? a. 3/6 b. 2/3 c. 12/30 d. 6/10
Veronika [31]
I am pretty sure it is (a) because 9 and 15 and 3 and 6 can be all divided by 3
4 0
3 years ago
A manufacturer wants to make open tin boxes from pieces of tin with dimensions 8 in. by 15 in. by cutting equal squares from the
Stells [14]

Answer:

\frac{5}{3} in

Step-by-step explanation:

Let x be the side of square.

Length of box=8-2x

Width of box=15-2x

Height of box=x

Volume of box=L\times B\times H

Substitute the values then we get

Volume of box=V(x)=(8-2x)(15-2x)x=(15x-2x^2)(8-2x)

V(x)=120x-30x^2-16x^2+4x^3

V(x)=4x^3-46x^2+120x

Differentiate w.r.t x

V'(x)=12x^2-92x+120

V'(x)=0

12x^2-92x+120=0

3x^2-23x+30=0

3x^2-18x-5x+30=0

3x(x-6)-5(x-6)=0

(x-6)(3x-5)=0

x-6=0\implies x=6

3x-5=0\implies x=\frac{5}{3}

Again differentiate w.r.t x

V''(x)=24x-92

Substitute x=6

V''(6)=24(6)-92=52>0

Substitute x=5/3

V''(5/3)=24(5/3)-92=-52

Hence, the volume is maximum at x=\frac{5}{3}

Therefore, the side of the square ,x=\frac{5}{3} in cutout that gives the box the largest possible volume.

5 0
3 years ago
Which one is it A. B. C. or D.
Semmy [17]
La respuesta correcta el la letra D

4 0
3 years ago
I get confused a lot with the "or" and "and". Please help, I have a test tomorrow!!
kenny6666 [7]

"and" is where they intersect

"or" is adding both circles (only add the intersection once)

<u>Start at the end of the paragraph and work backwards:</u>

10 people like all 3 flavors so write 10 in the middle (where all 3 intersect).

*************************************************************************************************

26 like coffee and pecan so write 16 where those two circles intersect. (26 - 10 = 16, remember that 10 are already included in both circles)

15 like mint and pecan so write 5 where those two circles intersect (15 - 10 = 5, remember that 10 are already included in both circles)

22 like mint and coffee so write 12 where those two circles intersect (22 - 10 = 12, remember that 10 are already included in both circles).

************************************************************************************************

48 like pecan so write 17 in the big circle (48 - 10 - 16 - 5).  The intersections contain 5, 16, and 10, so that leaves a remainder of 17.

52 like coffee so write 14 in the big circle (52 - 10 - 16 - 12).  The intersections contain 12, 16, and 10, so that leaves a remainder of 14.

30 like mint so write 3 in the big circle (30 - 10 - 12 - 5).  The intersections contain 5, 12, and 10, so that leaves a remainder of 3.

*********************************************************************************************

Answers:

a) 17 (big pecan circle only)

b) 60 (sum of all numbers in both mint and coffee circles)

c) 23 (the sum of every circle and intersection is 77, subtract that from 100)

d) 32 (pecan circle and intersections but not the pecan/coffee intersection)

e) 16 (intersection of pecan and coffee without the mint)





4 0
4 years ago
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