Answer:
1. Proportional.
2. ce
3. Segment Addition Postulate.
Step-by-step explanation:
By the angle-angle similarity postulate, △YXZ∼△YZQ and △YXZ∼△ZXQ.
The corresponding sides of two similar triangles are proportional.
Since similar triangles have proportional sides, therefore
and ![\frac{b}{c}=\frac{e}{b}](https://tex.z-dn.net/?f=%5Cfrac%7Bb%7D%7Bc%7D%3D%5Cfrac%7Be%7D%7Bb%7D)
Solving the equation for a² and b² gives
and ![b^2=ce](https://tex.z-dn.net/?f=b%5E2%3Dce)
The value of a² is cf and the value b² is ce.
Adding these together gives
![a^2+b^2=cf+ce](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dcf%2Bce)
Factoring out the common segment gives
![a^2+b^2=c(f+e)](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%28f%2Be%29)
From the given figure it is clear that
(Segment Addition Postulate)
Using segment Addition Postulate, we get
![a^2+b^2=c(c)](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%28c%29)
On simplification, we get
![a^2+b^2=c^2](https://tex.z-dn.net/?f=a%5E2%2Bb%5E2%3Dc%5E2)
Therefore the required answers are 1. Proportional, 2. ce, 3. Segment Addition Postulate.